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Marina CMI [18]
3 years ago
5

Please help I'm confused on where to start and with the graph.

Physics
1 answer:
tankabanditka [31]3 years ago
3 0

I don't think anyone knows the answer

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Juliette sets the initial velocity to +10 m/s, the acceleration to zero, and clicks “start.” How can Shakina describe the subseq
ICE Princess25 [194]

Explanation :

It is given that :

The initial velocity of the car is 10 m/s.

Juliette sets the acceleration to zero.

We know that, acceleration a=\frac{v-u}{t}\

where,

u is the initial velocity and v is the final velocity.

So, final velocity will become 10 m/s.

Hence, the car will move with the constant velocity i.e. 10 m/s.

So, Shakina described that the car will move with the constant velocity of 10 m/s as acceleration is zero.  

5 0
3 years ago
If a spacecraft that seems to be motionless is deep space is given some type of quick push, what will happen?
Sergio [31]

According to the first Newton Law of Motion (sometimes called <u><em>Law of Inertia</em></u>):


An object at rest or describing a uniform straight line motion (<u>moving at constant velocity)</u>, will remain at rest or moving unless an external force is applied to it and changes its state of rest or motion.

In other words:

An object or body will keep its state of motion until an external force changes its state

<u>This means that </u><u>objects tend to remain in its state of motion</u><u>, and is the definition of the inertia</u>, as well.

Now, going back to the spacecraft in deep space of the question, if some force acts on it, the spacecraft will change its state and move in the same direction of the force applied.

It will also keep this path until another <u>external force</u> <em>stops</em>, <em>accelerates</em> or <em>changes</em> its direction.

Therefore, the right answer is C:


The spacecraft will move and will not stop until it is stopped by an equal and opposite force.  


Options A, B and D are <u>not correc</u>t because:

A) The spacecraft cannot stop by its own; this would break Newton’s Laws of Motion

B) In deep space there is not air resistance, is <u>vacuum.</u>

D) The spacecraft works in space


7 0
3 years ago
Read 2 more answers
Please answer as fast as possible
sineoko [7]

Explanation:

the pressure is given by P=hpg

where h is height,p is density, g is 10m/s²

thus P= 0.05m•13.6x10³•10

P=6.8x10³ Hgmm

3 0
3 years ago
What does increasing the speed of an object do to its potential energy?
JulijaS [17]
It does not affect the objects potential energy.
7 0
3 years ago
Read 2 more answers
A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
Jlenok [28]

Answer:

14.36 N

Explanation:

T_{1} = Tension in string 1

T_{2} = Tension in string 2

m_b = mass of the bar = 2.7 kg

W_b = weight of the bar

weight of the bar is given as

W_b = m_{b} g = (2.7) (9.8) = 26.46N

m_m = mass of the bar = 1.35 kg

W_m = weight of the monkey

weight of the monkey is given as

W_m = m_{m} g = (1.35) (9.8) = 13.23N

Using equilibrium of torque about left end

W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33 N

Using equilibrium of force in vertical direction

T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36 N

7 0
3 years ago
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