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Dvinal [7]
3 years ago
9

Calculate the wavelength of an electron mass 9.1*10^-31kg moving with a velocity of 2.0*10^6m/s (h=6.63*10^-34Js) (Hint: De Brog

lie's wavelength)
Physics
1 answer:
Inga [223]3 years ago
8 0

Answer:

Wavelength, \lambda=3.64\times 10^{-10}\ m

Explanation:

We have,

Velocity an electron is 2\times 10^6\ m/s

Mass of an electron is 9.1\times 10^{-31}\ kg

It is required to find the wavelength of electron. The De-Broglie wavelength of an electron is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^6}\\\\\lambda=3.64\times 10^{-10}\ m

So, the wavelength of an electron is 3.64\times 10^{-10}\ m.

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What are the four planets that orbit closets to the sun
Elden [556K]

Answer:

Explanation:The four closest to the sun — Mercury, Venus, Earth and Mars — are the terrestrial planets. They have rocky surfaces enclosed by relatively shallow atmospheres.

8 0
3 years ago
A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
vesna_86 [32]

I thought you were going to ask for the resistance of the unknown
series resistor.  Since you only want the equivalent resistance of the
circuit, you don't even need to know the resistance of the lamp.

I = E / R

Current through the circuit = (voltage of the battery) / (circuit resistance).
  
                                                  0.5 = (12) / R

Multiply each side by  'R' :    (0.5) R = 12

Multiply each side by  2 :      <em>R = 24 ohms</em>


(Since the resistance of the lamp is 10 ohms, the
unknown series resistor is the other 14 ohms.)
7 0
3 years ago
A centrifuge rotates so that 0. 25 m from the center is traveling at 343 m/s (the speed of sound). How many RPM is this? What is
andrew-mc [135]

Answer:

[13,101 RPM]

[1372 rad/s]

Explanation:

8 0
2 years ago
You are tasked with calibrating the springs for a pinball machine. Your method of testing the springs is by attaching masses ont
choli [55]

Answer:

490.5\ \text{N/m}

Explanation:

m = Mass attached to spring = 14 kg

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

x = Displacement of spring = 78-50=28\ \text{cm}

k = Spring constant

The force balance of the system is given by

kx=mg\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{14\times 9.81}{0.28}\\\Rightarrow k=490.5\ \text{N/m}

The spring constant for that spring is 490.5\ \text{N/m}.

6 0
3 years ago
An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux
zhenek [66]

Answer:

\phi=1.56\times 10^{-5}\ Wb

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H

We have,

L=\dfrac{N\phi}{I}, \phi is magnetic flux

\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb

So, the magnetic flux is 1.56\times 10^{-5}\ Wb.

8 0
3 years ago
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