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Dvinal [7]
3 years ago
9

Calculate the wavelength of an electron mass 9.1*10^-31kg moving with a velocity of 2.0*10^6m/s (h=6.63*10^-34Js) (Hint: De Brog

lie's wavelength)
Physics
1 answer:
Inga [223]3 years ago
8 0

Answer:

Wavelength, \lambda=3.64\times 10^{-10}\ m

Explanation:

We have,

Velocity an electron is 2\times 10^6\ m/s

Mass of an electron is 9.1\times 10^{-31}\ kg

It is required to find the wavelength of electron. The De-Broglie wavelength of an electron is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^6}\\\\\lambda=3.64\times 10^{-10}\ m

So, the wavelength of an electron is 3.64\times 10^{-10}\ m.

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Is it possible that a speed of 254 and a speed of 100 could be the same speed?
EastWind [94]
Not if both speeds are in the same units.

However, if the 254 is 'centimeters per time' and the 100 is 'inches per time',
then the speeds are equal.
4 0
3 years ago
find a magnitude of the force such that if the act at right angle there resultant is √10N but if the act of 50° the resultant is
Readme [11.4K]

Explanation:

Let magnitude of the two forces be x and y.

Resultant at right angle R1= √15N) and at

60 degrees be R2= √18N.

Now, R1 = √(x² + y²) = √15,

R2= √(x² + y² +2xycos50) = √18.

So x² + y² = 15,

and x² + y² + 1.29xy = 18,

therefore 1.29xy = 3,

y = 3/1.29x.

y = 2.33/x

Now, x2 + (2.33/x)2 = 15,

x² + 5.45/x² = 15

multiply through by x²

x⁴ + 5.45 = 15x²

x⁴ - 15x2 + 5.45 = 0

Now find the roots of the equation, and later y. The two values of x will correspond to the

magnitudes of the two vectors.

Good luck

7 0
3 years ago
Which statement is supported by this scenario?
Temka [501]

Answer:

For Yanni, the speed of the ball is 15 m/s, and for the quarterback, the speed of the ball is 8 m/s.

Explanation:

6 0
3 years ago
Read 2 more answers
A. 2kg<br><br> B. 6kg<br><br> C. 8kg<br><br> D. 14kg
Sati [7]

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

7 0
3 years ago
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
Leto [7]

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
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