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Bond [772]
3 years ago
13

Of these choices, where would the most reactive nonmetal on the periodic table be located?

Physics
2 answers:
WINSTONCH [101]3 years ago
8 0
I think it might be D.) Group 17, period 5. but i'm not entirely sure<span />
Llana [10]3 years ago
7 0
D is the answer for sure

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A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
In addition to a reference point you also need distance and __________ to describe location
Lana71 [14]

displacement

btw in not sure

6 0
3 years ago
A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much
Pani-rosa [81]

Answer:

» Force is 200,000 Newtons

Explanation:

{ \tt{force =  \frac{impulse}{time} }} \\  \\ { \tt{force =  \frac{20000}{0.1} }} \\  \\ { \tt{force = 200000 \: newtons}}

8 0
2 years ago
Read 2 more answers
The tendency for an object at rest to remain at rest
Zarrin [17]
Inertia is the force in play here
7 0
3 years ago
Someone please help!! Will mark brainliest
11111nata11111 [884]

Answer:

d.

Explanation:

the arrow is starts at 0,0 and ends at 2,2

5 0
2 years ago
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