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Zanzabum
3 years ago
7

This is how osmium appears in the periodic table.A purple box has O s at the center and 76 above. Below it says osmium and below

that 190.23.
Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium?


a76

b114

c 190

d266
Chemistry
2 answers:
klemol [59]3 years ago
8 0

Answer:

114

Explanation:

plz make me brainiest

Musya8 [376]3 years ago
4 0
<h2>The answer is...</h2><h2 /><h2>There are <u>114</u> atoms on average in osmium.</h2>
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Formation of ammonia by nitrogen and hydrogen is habers process wher 28g N2 results in formation of 34g NH3
so 35g N2 will form 34*35/28=42.5g NH3 where it given that reaction takes place in excess of H2
N2+3H2 gives 2NH3
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This is an impossible formula. Pretend it is real.
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There are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound  Mn_{9}(ClO_{4}) _{2}. In one mole of the compound we have;

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Thus, there are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

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2 years ago
Why is the sun up sometimes but not other times?
MatroZZZ [7]

Answer: The Sun appears to move across the sky because the Earth rotates on its axis. ... When where you are is pointed toward the Sun, it is day. Then the Earth rotates you away from the Sun, and it is night.

Explanation:

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4 years ago
Which scientist performed the cathode ray experiment leading to the discovery of electrons
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The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

<h3>What is a cathode ray?</h3>

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The cathode ray was used by the scientist, J.J. Thomson to find the ratio of charge to mass (e/m) of the electrons.

Therefore, the scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

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6 0
2 years ago
A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?
horsena [70]

<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = \frac{44g}{77.46mL}\times 60mL=34.1g

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0
3 years ago
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