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3 years ago

The table describes how some substances were formed.

Chemistry

1 answer:

gogolik [260]3 years ago

6 0

Answer:

Formed by adding 5 g of sugar to 1 L of water

Explanation:

The substance formed by adding 5 g of suagr to 1 L of water is a mixture.

<em>A mixture is defined as two or more substances that are physically mixed but do not react together. It thus means that the component substances of a mixture can be retrieved through appropriate means of separations.</em>

<u>A mixture of sugar and water can be separated by evaporation. The mixture is heated and the vapor from the boiling water can be condensed to retrieve the water while the residue will give the sugar that was initially dissolved in it. </u>

The products formed from other descriptions in the illustration cannot be separated ordinarily and thus, are not considered to be mixture. The components have been chemically combined together.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

m is the mass

f is the force

From the question

mass = 3.5 kg

force = 35 N

We have

$a = \frac{35}{3.5} \\ = 10$

We have the final answer as

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3 years ago

Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of

Natalija [7]

Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = $\frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}$

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

$\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}$

$\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}$

We make a simplification because x<<< 0.0225:

$\frac{4x^3}{0.0225} =9.30*10^{-8}$

x = 8.058x10⁻⁴

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3 years ago

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kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

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