Answer:
3 * 10³J/s
Explanation:
Given :
Force applied, F = 300 N
Distance, d = 30 m
Time, t = 3 seconds
Power, P = Workdone / time
Recall :
Workdone = Force * distance
Workdone = 300 N * 30 m = 9000 Nm
Workdone = 9 * 10³ J
Power = (9 * 10³ J) / 3s
Power = 3 * 10³J/s
Answer - The given statement is false.
Explanation-
The members of knight of labour were opposing strikes and had a belief or boycott or arbitration.
A secret society was formed in 1869 by the tailors in Philadelphia and named Knights of labour. This union Organisation was formed to to get rights over equal pay if work is equal, abolish child labour, Work time of 8 hours and some graduated income tax reforms. This union was vertically organized.
Due to difference in electric potential.
<h3>What is Potential difference?</h3>
The amount of work in an electrical field to move a unit charge from one place to another is known as the electrical potential difference.
Here , the potential difference is the difference in electric potential between two charged substances.
Current is the flow of charges from one end end to another end of a conducting wire connected across a two terminals of a battery.
The potential difference is [provided by the battery across the two terminals due which the charges flow.
Current flow is from positive to negative terminals, indicating the movement of positive charges in that direction.
Hence , potential difference causes the electric charges to flow from one end of the battery .
Learn more about the flow of current : brainly.com/question/2264542
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Gravity?????????? or maybe like any object
Ans: Beat Frequency = 1.97HzExplanation:
The fundamental frequency on a vibrating string is

<span> -- (A)</span>
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>

<span> = 197.97Hz </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>