1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ludmilkaskok [199]
3 years ago
7

Acid indigestion is sometimes neutralized with an antacid such as magnesium hydroxide (Mg(OH)2). What products will be released

when the antacid is mixed with the hydrochloric acid in the stomach
Chemistry
1 answer:
NemiM [27]3 years ago
7 0

Answer:

Magnesium chloride and water  

Explanation:

Mg(OH)₂ + 2HCl ⟶                MgCl₂                +   2H₂O

                                    magnesium chloride        water

You might be interested in
Find the empirical and the molecular formula of acetylene gas composed of 92.26 percent carbon and 7.74 percent hydrogen
Hitman42 [59]

Answer:

CH

Explanation:

92.26% = 92.26 g

7.74% = 7.74 g

carbon is 92.26 x 1 mole/12.011 = 7.68

hydrogen is 7.74 x 1 mole/1.008 = 7.68

carbon 7.68 ÷ hydrogen 7.68 = 1

so 1 is your subscript for both carbon and hydrogen

6 0
3 years ago
3. At a pressure of 405 kPa, the volume of a gas is 6.00 cm
monitta

The pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

Explanation:

In the present problem, the temperature is said to remain at constant and there is change in the pressure. So according to Boyle's law, the relationship between pressure and volume of any gaseous objects are inversely related to each other. In other words, the pressure attained by gas molecules in a container will be inversely proportional to the volume of the gas molecules occupied in the container, at constant temperature.

V=\frac{1}{P}

So, if two volumes V₁ and V₂ are considered, then their respective pressure will be represented as P₁ and P₂. Then, as per Boyle's law,

V_{1}P_{1}=V_{2}P_{2}

So let us consider, V₁ = 6 cm³ and V₂ = 4 cm³ and pressure P₁ = 405 kPa and we have to determine P₂.

Then,  6*405=5*P_{2}\\ \\P_{2}=\frac{2430}{5} =486 kPa

So, the pressure at new volume of 4 cm³ is 486 kPa. It can be seen that as there is decrease in the volume, there is an increase in the pressure. So it satisfied the Boyle's law.

Thus, the pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

6 0
3 years ago
OK OK ONE MORE TRY
babunello [35]
Your question can be found online! Just draw one of these diagrams

7 0
3 years ago
Read 2 more answers
Can someone please answer the question, <br>What is heat?​
Levart [38]

Answer:

hot

Explanation:

6 0
3 years ago
Read 2 more answers
Why do we sometimes use roman numerals in naming ionic compounds?
Blababa [14]
Roman numerals are used in naming ionic compounds when the metal cation forms more than one ion. The metals that form more than one ion are the transition metals, although not all of them do this.
6 0
3 years ago
Read 2 more answers
Other questions:
  • 2.5 moles of oxygen react with 3.5 moles of hydrogen according to the following balance equation: 2H2 + 1 O2 —&gt; 2 H2O. What i
    9·1 answer
  • How many mol molecule oxygen are 3 mol oxygen atoms
    8·1 answer
  • What is 9,865 km expressed in scientific notation? A. 9.865 × 100 km B. 9.865 × 102 km C. 9.865 × 103 km D. 9.865 × 10-3 km
    15·1 answer
  • Which group on the periodic table contains only metals?
    5·1 answer
  • Which of the following is not a feature of iron (III) oxide?
    10·2 answers
  • Which element has 51 protons in its nucleus?
    6·1 answer
  • How would you describe the jumping pattern of the green frog bellow?
    10·1 answer
  • Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types
    14·1 answer
  • Magneisum and Bromine formation
    11·1 answer
  • Who is the first to write an atomic theory based upon experimentation?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!