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VikaD [51]
3 years ago
15

An experiment invilves three charges objects: A, B, and C. Object A repels object B and attracts onject C. object C ir repelled

by ebonite charged with fur. What is the charge on the object?
Physics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

A and B is positive charge

C_negative

Explanation:

because when an ebonite is rubbed with fur produce negative charge due to law of electrostatic like charge repel and unlike attract

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A 20 N unbalanced force causes an object to accelerate at 1.5 m/s2. What is the mass of the object?
Ket [755]

<u>Answer:</u>

Force = 20N

acceleration (a) = 1.5 m/s²

Mass of object (m) = ?

<u>From Newtons II law</u>

                   <em>    F = m. a N</em>

                        m =  F/a

                        m = 20/1.5

                      <em>  m = 13.34 Kg</em>

<em>Mass of an object is 13.34 Kg</em>

8 0
4 years ago
A 300N box on a 43 degree angle.
Ksenya-84 [330]

Answer:is this a question??? I’m so confused

Explanation:

7 0
3 years ago
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
4 years ago
Through x rays is harmful for human health it is used in medical field why?
ipn [44]
It is strong enough to penetrate through flesh but not bone so we can see if there are fractures or breaks in our skeleton
6 0
3 years ago
When the starter motor on a car is engaged, there is a 310 A current in the wires between the battery and the motor. Suppose the
Blababa [14]

Answer:

Diameter will be 351.42 mm

Explanation:

We have given current flowing in the copper wire i = 310 A

Voltage drop across the wire V = 0.55 volt

We know that resistance is given by R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega

Length of the copper wire l = 1 m

Resisitivity of the copper wire \rho =1.72\times 10^{-8}\Omega m

We know that resistance R=\frac{\rho l}{A}

0.00177=\frac{1.72\times 10^{-8}\times  1}{A}

A=969.4545\times 10^{-8}m^2

As area A=\pi r^2

3.14\times r^2=969.4545\times 10^{-8}

r=17.57\times 10^{-4}m

So diameter d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m = 351.42 mm

3 0
4 years ago
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