Answer:
1.603 s
Explanation:
Given that
Initial mass, = 0.45 kg
Initial period, = 1.45 s
Initial radius, = 0.14 m
Final mass, = 0.55 kg
Final period, = ?
Final radios, = 0.14 m
Since we are finding the rotation period of two masses of same radius, we can assume that the outward force is the same in both cases. This means that
m₁r₁ω₁² = m₂r₂ω2²
Where, ω = 2π/T, on substituting, we have
0.45 * 0.14 * (2π / 1.45)² = 0.550 * 0.14 * (2π / T₂)²
0.45 / 1.45² = 0.550 / T₂²
T₂² = 0.550 * 1.45² / 0.45
T₂² = 2.56972
T₂ = √2.56972
T₂ = 1.603 sec
I would have to say that 'B' and 'D' are both correct.
Increasing the voltage that you're using to operate a circuit
causes the current in the circuit to increase. But current is
just the number of electrons that are flowing through it. So
right there, you have the increase in the number of charges.
Now, every electron that flows through the circuit gives up
some energy on the way. So if there are more electrons
making the trip, then more energy has been put into the circuit.
Jessica, I absolutely love your printing.
I wish I could print so clearly.
You can tell because the line bends and the closer it is to horizontal or past horizontal it is more dense
Answer:
Squats involve flexion (forward motion) and extension (backward on the way up), so would fit into the sagittal plane. Frontal plane motion would include leaning from left to right as in sidebends and lateral raises, or perhaps you might picture jumping jacks for a good image of movement along the frontal plane.
Answer:
(A) Frictional force will be 103.7276 N
(B) Coefficient of friction
Explanation:
We have given
mass of the box m = 25 kg
Angle ![\Theta =27^{\circ}[/text]Acceleration [tex]a=0.3m/sec^2](https://tex.z-dn.net/?f=%5CTheta%20%3D27%5E%7B%5Ccirc%7D%5B%2Ftext%5D%3C%2Fp%3E%3Cp%3EAcceleration%20%5Btex%5Da%3D0.3m%2Fsec%5E2)
Apply Newton's second law of motion ,
Vertically :
= mg cosθ
= 
Horizontally :
mg sinθ - F = ma
A)
frictional force F= mg sinθ - ma
= 
B)
Coefficient of friction 