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Brums [2.3K]
3 years ago
5

An offshore oil platform houses a drill for drilling oil. The drill descends from the platform and enters the ocean. At the bott

om of the ocean, the drill starts to dig into the rock. It continues drilling into the rock for another 7,000 feet and then stops. Where does the drill stop?
Physics
2 answers:
bezimeni [28]3 years ago
4 0

Answer:

in the geosphere

Explanation:

butalik [34]3 years ago
3 0

Answer:

Geosphere

Explanation:

I did it and got the answer right.

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How could you use a rock to measure the height of your ceiling?
Annette [7]

Answer:

I mean this is what I think

Explanation:

you would need to place a rock on top of each other until you reach the ceiling

It seems logical to me

7 0
3 years ago
Hai ô tô khởi hành cùng lúc từ A,B cách nhau 20 km chuyển động theo hướng từ A đến B vs vận tốc lần lượt là 60km/h và 40km/h
sdas [7]

Answer:

áp dụng công thức v = s/t

s là dộ dài qduong

v là vận tốc

t là thời gian

xuyên suốt 2 câu hỏi đều dùng công thức này

Explanation:

6 0
2 years ago
What planet has a visible mark referred to as the the Great Red Spot?
vivado [14]

Jupiter  that is the answer

good luck

6 0
3 years ago
What is the velocity of an object that has been in free fall for 1.5s?
Crank

Answer:

D. 15 m/s downward

Explanation:

v = at + v₀

v = (-9.8 m/s²) (1.5 s) + (0 m/s)

v = -14.7 m/s

Rounded to two significant figures, the answer is D, 15 m/s downward.

8 0
3 years ago
How do your results from ray tracing compare to your results from using the thin-lens equation?
EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image <em>(image distance can be negative or positive depending on the nature of the image</em>).

According to the lens equation

\frac{1}{f} = \frac{1}{u} + \frac{1}{v} where;

f is the focal length  of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

Hence the focal length of the convex lens is 20cm

7 0
3 years ago
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