2. How much energy does a 5 kg tennis ball have<br> that is sitting on a shelf that is 2m high?

There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much

PIT_PIT [208]

P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.

5 0

3 years ago

Please select the word from the list that best fits the definition

alexdok [17]

Answer:

yuuuhhhhhhh

Explanation:

it maxed Imao

4 0

3 years ago

Read 2 more answers

Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its

ruslelena [56]

Answer:

a

The orbital speed is $v= 2.6*10^{3} m/s$

b

The escape velocity of the rocket is $v_e= 3.72 *10^3 m/s$

Explanation:

Generally angular velocity is mathematically represented as

$w = \frac{2 \pi}{T}$

Where T is the period which is given as 1.6 days = $1.6 *24 *60*60 = 138240 sec$

Substituting the value

$w = \frac{2 \pi}{138240}$

$= 4.54*10^ {-5} rad /sec$

At the point when the rocket is on a circular orbit

The gravitational force = centripetal force and this can be mathematically represented as

$\frac{GMm}{r^2} = mr w^2$

Where G is the universal gravitational constant with a value $G = 6.67*10^{-11}$

M is the mass of the earth with a constant value of $M = 5.98*10^{24}kg$

r is the distance between earth and circular orbit where the rocke is found

Making r the subject

$r = \sqrt[3]{\frac{GM}{w^2} }$

$= \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }$

$= 5.78 *10^7 m$

The orbital speed is represented mathematically as

$v=wr$

Substituting value

$v= (5.78*10^7)(4.54*10^{-5})$

$v= 2.6*10^{3} m/s$

The escape velocity is mathematically represented as

$v_e = \sqrt{\frac{2GM}{r} }$

Substituting values

$= \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }$

$v_e= 3.72 *10^3 m/s$

7 0

3 years ago

Convert 15 joule into erg.

GuDViN [60]

Answer:

<h2><u>Joule</u><u>:</u></h2>

1 Joule of work is said to be done when a force of 1 Newton is applied to move/displace a body by 1 metre.

1 Joule= 1 Newton × 1 metre

1 Newton is the amount of force required to accelerate body of mass 1 kg by 1m/s²

So units of N is kgm/s²

So,

1 Joule

=1kgm/s² × m

=1kgm²/s²

1 erg is the amount of work done by a force of 1 dyne exerted for a distance of one centimetre.

1 Erg =1 Dyne × 1 cm

1 dyne is the force required to cause a mass of 1 gram to accelerate at a rate of 1cm/s².

1 Erg=1 gmcm/s² × cm

1 Erg=1 gmcm/s² × cm=1gmcm²/s²

this is what you need to convert 1gmcm²/s² to 1kgm²/s²

<h3><u>what you need to know for conversion</u></h3>

[1gm=0.001kg

1cm²

=1cm ×1cm

=0.01 m × 0.01 m

=0.0001m²

second remains constant

]

So,

1gmcm²/s²

=0.001kg×0.0001m²/s²

=0.001kg×0.0001m²/s² =0.0000001kgm²/s²

Hence,

<h3><u>1 Erg</u><u>=</u><u>0.0000001</u><u> </u><u>Joule</u></h3><h3><u>1</u><u> </u><u>Joule</u><u>=</u><u>1</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>Erg</u></h3>

3 0

3 years ago

Read 2 more answers

An ant clings to the outside edge of the tire of an exercise bicycle. When you start pedaling, the ant's speed increases from ze

konstantin123 [22]

Answer:

1- 3.64 m/s

2- 0.28 m

3- 70.8 rad

4- 19.8 m

Explanation:

see attachment

3 0

3 years ago

2. How much energy does a 5 kg tennis ball have that is sitting on a shelf that is 2m high?