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Vesna [10]
3 years ago
14

Where is earth's magnetic north pole located?

Physics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:ellesmere island, Canada

andre [41]3 years ago
4 0

Answer: it is located over Ellesmere Island, Canada

Explanation

it is now drifting away from North America and toward Siberia.

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Explain percentage error​
skelet666 [1.2K]

Answer:

Percent error (percentage error) is the difference between an experimental and theoretical value, divided by the theoretical value, multiplied by 100 to give a percent

Explanation:

found this off google

6 0
3 years ago
Please can someone answer this question ​
EastWind [94]
B????????? I thinkkkkk
7 0
3 years ago
Read 2 more answers
What kinds of bonds can happen between the elements of a compound
Anit [1.1K]
What kinds of bonds can happen between the elements of a compound?

<span>Covalent and Ionic</span>

4 0
3 years ago
1. A satellite (mass = 4.44 x 109 kg) travels in orbit around the Earth at a distance of 1.9 x 10'm above
Nuetrik [128]

Answer:

The force of gravitational attraction between the satellite and Earth is 2.587\times 10^{10} newtons.

Explanation:

Statement is incorrect. Correct statement is:

<em>A satellite (</em>m = 4.44\times 10^{9}\,kg<em>) travels in orbit around the Earth at a distance of </em>1.9\times 10^{6}\,m<em> above Earth's surface. What is the force of gravitational attraction between the satellite and Earth?</em>

The gravitational force experimented by the satellite (F), in newtons, is calculated by Newton's Law of Gravitation, whose equation is defined by following formula:

F = \frac{G\cdot m \cdot M}{R^{2}} (1)

Where:

G - Gravitational constant, in cubic meters per kilogram-square second.

m - Mass of the satellite, in kilograms.

M - Mass of the Earth, in kilograms.

R - Distance of the satellite with respect to the center of the Earth, measured in meters.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m = 4.44\times 10^{9}\,kg, M = 5.972\times 10^{24}\,kg and R = 8.271\times 10^{6}\,m, then the force of gravitational attraction between the satellite and Earth is:

F = 2.587\times 10^{10}\,N

The force of gravitational attraction between the satellite and Earth is 2.587\times 10^{10} newtons.

6 0
3 years ago
2. A 3 kg ball is thrown downward at 4 m/s from a height of 1.5 m. a. What is the kinetic energy of the ball as it leaves the th
VikaD [51]

Answer:

a) 24 J

b) Gravitational Force

c) 45 J

d) 0

e) 6.782m/s

Explanation:

a) m = 3kg

v = 4m/s

h = 1.5m

KE = ?

0.5 * 3 * 16 = 24J

b) Gravitational force

c) F = ma = 3 * 10 = 30N

Work done = Force * distance = 30 * 1.5 = 45J

d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving

e) velocity of ball as it strikes the ground = v

v^{2} - u^{2} = 2as where

v is the velocity as it strikes the ground

u is the initial velocity

a is acceleration

s is the distance

Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it

u = 4m/s

a = 10

s = 1.5

=>  v = \sqrt{2as + u^{2} }

= \sqrt{(2*10*1.5) + 16}

= \sqrt{46} = 6.782m/s

7 0
3 years ago
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