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3 years ago

An athlete whirls a 7.00 kg hammer 1.8 m from the axis of rotation in a horizontal circle, as

Physics

1 answer:

iogann1982 [59]3 years ago

5 0

Answer:

A-500 N

Explanation:

The computation of the tension in the chain is shown below

As we know that

F = ma

where

F denotes force

m denotes mass = 7

And, a denotes acceleration

Now for the acceleration we have to do the following calculations

The speed (v) of the hammer is

v = Angular speed × radius

where,

Angular seed = 2 × π ÷ Time Period

So, v = 2 × π × r ÷ P

v = 2 × 3.14 × 1.8 ÷ 1

= 11.304 m/s

Now

a = v^2 ÷ r

= 70.98912 m/s^2

Now the tension is

T = F = m × a

= 7 × 70.98912

= 496.92384 N

= 500 N

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The box leaves position x=0 with speed v0. The box is slowed by a constant frictional force until it comes to rest at position x

Diano4ka-milaya [45]

Answer:

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3 years ago

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Answer:

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V2 ?

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