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Phantasy [73]
3 years ago
8

W. E. B. Du Bois and Booker T. Washington most

Chemistry
1 answer:
Xelga [282]3 years ago
8 0
The answer is (3) methods to achieve racial equality.

Both Du Bois and Washington had different views on how to promote equality, Du Bois emphasized education and immediate political equality while Washington was more concerned with economic equality in industrial and agriculture
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A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?
MatroZZZ [7]
Letter d, because they are both alkali metals (group one)
8 0
3 years ago
Read 2 more answers
PLS HELP ME I WILL GIVE BRAINLIEST TO U I JUST NEED ANSWERS ASAP
elena55 [62]

Answer:

is this multiple choice just wondering

4 0
3 years ago
Which of these characteristics best describes a basic solution?
mario62 [17]
I believe the correct answer would be that it feels slippery. Being slippery or soapy is one characteristic of a base. This due to the fact that it dissolves the oils and fatty acids from the skin.  Other characteristics would be that it turns litmus paper blue and has a bitter taste.
5 0
3 years ago
The enzyme, phosphoglucomutase, catalyzes the interconversion
Fittoniya [83]

Answer:

K_{eq = 19

ΔG° of the reaction forming glucose 6-phosphate =  -7295.06 J

ΔG° of the reaction  under cellular conditions = 10817.46 J

Explanation:

Glucose 1-phosphate     ⇄     Glucose 6-phosphate

Given that: at equilibrium, 95% glucose 6-phospate is  present, that implies that we 5% for glucose 1-phosphate

So, the equilibrium constant K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq= \frac{0.95}{0.05}

K_{eq = 19

The formula for calculating ΔG° is shown below as:

ΔG° = - RTinK

ΔG° = - (8.314 Jmol⁻¹ k⁻¹ × 298 k ×  1n(19))

ΔG° = 7295.05957 J

ΔG°≅ - 7295.06 J

b)

Given that; the concentration  for  glucose 1-phosphate = 1.090 x 10⁻² M

the concentration of glucose 6-phosphate is 1.395 x 10⁻⁴ M

Equilibrium constant  K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq}= \frac{1.395*10^{-4}}{1.090*10^{-2}}

K_{eq} = 0.01279816514  M

K_{eq} = 0.0127 M

ΔG° = - RTinK

ΔG° = -(8.314*298*In(0.0127)

ΔG° = 10817.45913 J

ΔG° = 10817.46 J

5 0
3 years ago
What was the chemical purpose of heating the MnSO4⋅H2O? Why is this procedure important?
Alla [95]

The chemical purpose of heating the MnSO4⋅H2O is to eliminate water with the formation of new compounds.

<h3>Dehydration reactions</h3>

Dehydration reaction is a type of chemical reaction that involves the removal of water which would eventually lead to the formation of a new compound.

The molecule of MnSO4⋅H2O contains a molecule of water(H2O). After heating of the molecule, water is lost giving rise to the dry compound MnSO4.

Other examples of dehydration reactions are:

  • Reactions that produce acid anhydrides.

  • Reactions that involve the production of polymers.

  • Reaction of sucrose with concentrated sulfuric acid

Therefore, the chemical purpose of heating the MnSO4⋅H2O is to eliminate water with the formation of new compounds.

Learn more about dehydration here:

brainly.com/question/12261974

8 0
2 years ago
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