The average kinetic energy and rms speed of N₂ molecules at STP is
and 
Given,

The average kinetic energy of a molecule is given by,
where k is the Boltzmann constant and Tis the absolute temperature of the gas.


The rms speed of
molecules is given by

The average kinetic energy of a gas's particles is inversely related to its temperature. As the gas warms, the particles must travel more quickly since their mass is constant.
The average kinetic energy (K) is equal to one half of the mass (m) of each gas molecule times the RMS speed (vrms) squared.
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A compound contains two or more elements chemically combined
Answer:

Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:

Best regards,
Its a single Displacement reaction