Answer:
All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons.
Explanation:
Answer:
Explanation:
We are given the mass of two reactants, so this is a limiting reactant problem.
We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 17.03 32.00 18.02
4NH₃ + 5O₂ ⟶ 4NO + 6H₂O
m/g: 70.1 70.1
Step 1. Calculate the moles of each reactant
Step 2. Identify the limiting reactant
Calculate the moles of H₂O we can obtain from each reactant.
From NH₃:
The molar ratio of H₂O:NH₃ is 6:4.
From O₂:
The molar ratio of H₂O:O₂ is 6:5.
O₂ is the limiting reactant because it gives the smaller amount of H₂O.
Step 3. Calculate the theoretical yield.
Answer:
The answer is
<h3>3.75 × 10²⁴ atoms of Al</h3>
Explanation:
To find the number of atoms of Al given it's number of moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 6.23 mol
We have
N = 6.23 × 6.02 × 10²³
We have the final answer as
<h3>3.75 × 10²⁴ atoms of Al</h3>
Hope this helps you
False; an ionic bond generally occurs between a nonmetal and a metal; for example, NaCl.
Answer:
the acid has been saturated with the base.
Explanation: