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Alborosie
3 years ago
5

A scientist studying an organism and has classified it as an animal which statement must be true about the organism

Chemistry
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

can you add the answer choices

Explanation:

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Calculate the half-life of different radioactive sources.
otez555 [7]
The rate at which a radioactive<span> isotope decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a </span>radioactive material<span> to disintegrate. </span>Half-lives<span> for </span>various radioisotopes<span> can range from a few microseconds to billions of years.
</span>.
back at it again with that answer
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zane
7 0
3 years ago
How many formula units are in 325 grams of iron (III) chloride?
OLEGan [10]

Answer:

1.204 × 10^24 formula units

Explanation:

Using the following formula to convert mass of iron (III) chloride to moles;

mole = mass/molar mass

Molar mass of FeCl3 = 56 + 35.5(3)

= 56 + 106.5

= 162.5g/mol

Mole = 325/162.5

mole = 2mol

Next, to calculate the formula units of FeCl3, we multiply the number of moles of FeCl3 by Avagadro number (6.02 × 10^23)

Formula units of FeCl3 = 2 × 6.02 × 10^23

12.04 × 10^23

= 1.204 × 10^24 formula units.

7 0
3 years ago
Consider the reaction between no and cl2 to form nocl: 2no(g)+cl2(g)⇌2nocl(g) a reaction mixture at a certain temperature initia
AlladinOne [14]

Answer:

Kc = 0.402.

Explanation:

  • We can calculate Kc from the relation: Kc = [NOCl]² / [NO]²[Cl₂].
  • [NOCl] = 0.30 M, [NO] = 0.65 M, and [Cl₂] = 0.53 M.
  • Now, we can get Kc:
  • Kc =  [NOCl]² / [NO]²[Cl₂] = (0.30 M)² / [(0.65 M)².(0.53 M)] = 0.402.
8 0
3 years ago
What is the medical term for ringing, buzzing, or hissing in the ears?
Thepotemich [5.8K]
Tinnitus is the ringing in ears or buzzing and hissing
7 0
3 years ago
A 0.610 m aqueous solution of kbr has a total mass of 75.0 g. what masses of solute and solvent are present?
Drupady [299]
To determine the masses of each component, we need to know the concentration first in terms of molality which is mol per mass of solution. Assuming the density of the solution is equal to that of water we would find:

molality = 0.160 mol KBr / L ( 1 L / 1 kg solution ) = 0.160 mol KBr / kg solution

mass KBr = 0.160 mol KBr / kg solution (.0750 kg solution ) ( 119 g KBr / mol KBr ) = 1.428 g KBr

mass solvent = 75 - 1.428 = 73.572 g water
8 0
3 years ago
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