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Lena [83]
3 years ago
11

Help on two science questions please!!

Chemistry
2 answers:
ioda3 years ago
4 0

Number 2 I believe is D and number 3 is most likely A

tamaranim1 [39]3 years ago
3 0

Answer:

2) The clothes picked up opposite charges which caused them to cling to each other.

3) A crinkled-up ball of aluminum foil will conduct the charges and remove the charges from the clothes.

Explanation:

I'm sure. Like pretty sure.

Hope this helped lots and lots,

sincerely, me

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When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from
IgorLugansk [536]

The question is incomplete, here is the complete question.

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g S_8.

Answer : The mass of silver sulfide is produced from a mixture is 3.44 grams.

Explanation : Given,

Mass of Ag = 3.0 g

Mass of S_8 = 3.0 g

Molar mass of Ag = 107.8 g/mole

Molar mass of S_8 = 256 g/mole

Molar mass of Ag_2S = 247.8 g/mole

First we have to calculate the moles of Ag and S_8.

\text{ Moles of }Ag=\frac{\text{ Mass of }Ag}{\text{ Molar mass of }Ag}=\frac{3.0}{107.8g/mole}=0.0278moles

\text{ Moles of }S_8=\frac{\text{ Mass of }S_8}{\text{ Molar mass of }S_8}=\frac{3.0g}{256g/mole}=0.0117moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

16Ag(s)+S_8(s)\rightarrow 8Ag_2S(s)

From the balanced reaction we conclude that

As, 16 mole of Ag react with 1 mole of S_8

So, 0.0278 moles of Ag react with \frac{0.0278}{16}=0.00174 moles of S_8

From this we conclude that, S_8 is an excess reagent because the given moles are greater than the required moles and Ag is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag_2S

From the reaction, we conclude that

As, 16 mole of Ag react to give 8 mole of Ag_2S

So, 0.0278 moles of Ag react to give \frac{0.0278}{16}\times 8=0.0139 moles of Ag_2S

Now we have to calculate the mass of Ag_2S

\text{ Mass of }Ag_2S=\text{ Moles of }Ag_2S\times \text{ Molar mass of }Ag_2S

\text{ Mass of }Ag_2S=(0.0139moles)\times (247.8g/mole)=3.44g

Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.

4 0
4 years ago
Running for presindentr
irina1246 [14]

Answer:

ok will do

Explanation:

moo

6 0
4 years ago
Describe how oxidation and reduction involve electrons, change oxidation numbers, and combine in oxidation reduction reactions
borishaifa [10]

Answer: Oxidation is defined as the reaction in which there is loss of electrons. It is accompanied by increase in oxidation number.

Zn\rightarrow Zn^{2+}+2e^{-}

Zinc in solid state has oxidation number of zero and on losing electrons changes to Zn^{2+} with oxidation number of +2.

Reduction is defined as the reaction in which there is gain of electrons. It  is accompanied by decrease in oxidation number.

2H^++e^{-}\rightarrow H_2

Hydrogen ions with +1 oxidation state gains electrons and converts to molecular hydrogen with oxidation state of zero.

In the given redox reaction, both oxidation and reduction takes place. They go hand in hand.

Zn+H_2SO_4\rightarrow ZnSO_4 +H_2

Zinc converts to Zn^{2+} and gets oxidized. H^+ gains electron and convert to H_2.




4 0
3 years ago
Newtons second law practice
Dima020 [189]

Answer: Motion

Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration. Learn how to use the formula to calculate acceleration.

5 0
3 years ago
At 20 °C the vapor pressure of pure benzene (C6H6) is 75.0 torr, and that of toluene (C7H8) is 22.0 torr. Assume that benzene an
8090 [49]

Answer:

mole fraction benzene = 0.62

mole fraction toluene   = 0.38

Explanation:

Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of  the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:

<h2>p total = x₁  P⁰₁ + x₂  P⁰₂</h2>

where x1 and x2 for this solution denote the mole fractions of  benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.

Solving the algebraic equation:

75 x₁ + 22 x₂  = 55

75 x₁ + 22 ( 1- x₁) = 55   (since x₁ + x₂ = 1)

75 x₁ + 22 - 22 x₁ = 55

53 x₁  = 33

x₁ = 0.62  

x₂ = 1 - 0.62 = 0.38

6 0
3 years ago
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