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IgorC [24]
2 years ago
13

Pls help and solve this problem. I don't have an idea to solve this.

Engineering
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

MIS HIEVOSTES bbbbbbbbbbbb MIS HUEVOTES

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When removing a diesel engine from a truck, Technician A says it is OK to disconnect an air con­ditioning hose, but the refriger
agasfer [191]

Answer:

Technician B is right.

Explanation:

Air conditioning refrigerant contains Freon R22 and R410a, which have been linked to environmental damages, including ozone depletion, global warming, and energy-inefficiency.  For environmentally-savvy entities and individuals, there is the modern move to a more environment-friendly refrigerant, known as R-32.   Technician A's advice to vent the refrigerant outside the shop is in bad taste.  He does not seem to be aware of the environmental footprint of such an action.  Venting gas outside, in addition to the environmental damages, is also a waste of resources, and therefore, costly.  This is why Technician B's advice should be preferred.

5 0
3 years ago
A screw is a simple machine that can be described as an inclined plane wrapped around a cylinder.
Phoenix [80]

Answer:

thanks thanks thanks thanks

Explanation:

7 0
3 years ago
Let S = { p q |p, q are prime numbers greater than 0} and E = {0, −2, 2, −4, 4, −6, 6, · · · } be the set of even integers. . Pr
Finger [1]

Answer:

prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S

Explanation:

Given that S = { p q |p, q are prime numbers greater than 0}

                    E = {0, −2, 2, −4, 4, −6, 6, · · · }

To prove  by constructing a bijection from S to E

detailed  solution attached below

After the bijection :

<em>prove that | S | = | E |</em> :  every element of S there is an Image on E , while not every element on E has an image on S

∴ we can say sets E and S are infinite sets

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3 years ago
If he wants to keep the height the same, what could the other dimensions be for him to get the volume he wants?
Fiesta28 [93]

tbm queria saber essa pergunta

8 0
3 years ago
Part A Engineering stress and strain are calculated using the actual cross-sectional area and length of the specimen. True or fa
Galina-37 [17]

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Explanation:

Engineering stress is the applied load divided by the original cross-sectional area of a material. It is also known as nominal stress. It can also be defined as the force per unit area of a material. Engineering Stress is usually in large numbers.

While Engineering strain is the amount that a material deforms per unit length in a tensile test.  It can also be defined as extension per unit length. It has no unit as it is a ratio of lengths. Engineering Strain is in small numbers.

5 0
3 years ago
Read 2 more answers
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