Answer:
it gains energy in a quantized amount
Explanation:
when we describe the energy of a particle as a quantized ,we mean that only certain values of energy are allowed....it can only gain the exact amount of energy needed to reach one of the higher energy levels
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<h3>
Answer:</h3>
Na₂S(s) → 2Na⁺(aq) + S²⁻(aq)
<h3>
Explanation:</h3>
We need to know:
<h3>What are decomposition reactions?</h3>
- Decomposition reactions are type of reactions in which a compound is broken down into two or more products.
- When a soluble substance or a compound is dissolved in water it forms an aqueous solution.
- When this happens the soluble compound such as ionic compounds ionizes to form ions.
- This is an example of decomposition reaction, since the ionic compound decomposes it ions making it.
- For example, sodium sulfide is an ionic compound that ionizes in water to form sodium and sulfide ions.
Na₂S(s) → 2Na⁺(aq) + S²⁻(aq)
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
Best regards!