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3 years ago

Scientific Method

Chemistry

1 answer:

Leona [35]3 years ago

4 0

Answer:

Problem, Variables, Hypothesis, Research, Procedure, Data, Conclusion.

Explanation:

First, you have to know what the problem that you're talking about is. Then, you have to know the independent, dependent, and controlled variables are in order to make a hypothesis. Then do research about the topic. After that, you make the procedure your experiment, if that's what your doing. Then after the experiment, you find the data. Using that data, you make a conclusion.

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What element is NaCl?

ale4655 [162]

Sorry but NaCl is a ionic compound not an element though it's made up of two elements sodium and chlorine

4 0

3 years ago

Read 2 more answers

If 27.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 32.40 mL of 0.185 M HCl, what is the concentration of the

zhannawk [14.2K]

Given information : Volume of HCl = 32.40 mL

$32.40 mL\times \frac{1 L}{1000 mL}$

Volume of HCl = 0.0324 L

Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)

Volume of Ca(OH)2 = 27.0 mL

$27.0 mL\times \frac{1 L}{1000 mL}$

Volume of Ca(OH)2 = 0.027 L

We need to find the concentration of Ca(OH)2.

To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.

$Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}$

Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.

Step 1 : Find the moles of HCl using its given volume and concentration.

$Moles = Concentration \times Volume in L$

$Moles = 0.185\frac{mol}{1L}\times 0.0324 L$

Moles of HCl = 0.005994 mol HCl

Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.

Mole ratio are the coefficient present in front of the compound in a balanced equation.

Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)

$(0.005994 mol HCl)\times \frac{(1 mol Ca(OH)2)}{(2 mol HCl)}$

Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2

Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.

$Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}$

Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L

$Concentration (Molarity) = \frac{(0.002997 mol)}{(0.027 L)}$

Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M

4 0

4 years ago

6. El oxígeno gaseoso se calienta a presión constate de 50 °C a 300 K. Se conoce que inicialmente el volumen del sistema era de

frez [133]

Answer:

El volumen final del sistema es 1.2L

Explanation:

La ley de Charles establece que el incremento de la temperatura de un gas produce un incremento en el volumen directamente proporcional cuando la presión permanece constante. La ecuación es:

V₁/T₁ = V₂/T₂

<em>Donde V es volumen y T temperatura absoluta de un gas en 1, el estado inicial y 2, su estado final.</em>

<em />

Reemplazando:

V₁ = 1.3L

T₁ = 50°C + 273.15K = 323.15K

V₂ = Incógnita

T₂ = 300K

1.3L/323.15K = V₂/300K

1.2L = V₂

<h3>El volumen final del sistema es 1.2L</h3>

3 0

3 years ago

The reaction between calcium acetate and lithium phosphate forms a white precipitate (the insoluble compound calcium phosphate),

kenny6666 [7]

Hello!

The coefficient for Lithium Acetate in the balanced chemical equation is 6

Why?

This is the reaction:

(CH₃COO)₂Ca(aq) + Li₃PO₄(aq) → Ca₃(PO₄)₂(s) + CH₃COOLi(aq)

For balancing the equation, we're going to apply the Law of Conservation of Mass, which states that matter is not created nor destroyed, and the number of atoms of each element should be the same on both sides of the equation, from that, the balanced equation is:

3(CH₃COO)₂Ca(aq) + 2Li₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6CH₃COOLi(aq)

Have a nice day!

3 0

4 years ago

a student forgot to include the 12 h2o when calculating the formula mass of the compound. how will the calculated percent yield

Marina CMI [18]

If the student forgot to calculate 12 H2O molecule from the compound, that means the compound molecular mass used will be much lower than it should. If the molecular mass calculated lower than it should, then the percent yield would be increased.
If the student fixes the compound mass, then the yield will become lower than the first result.

8 0

4 years ago