pH=2.7
<h3>Further explanation</h3>
Acetic acid = weak acid
![\tt [H^+]=\sqrt{Ka.M}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7BKa.M%7D)
Ka = acid ionization constant
M = molarity
Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵
![\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.222%7D%5C%5C%5C%5C%3D0.001998%3D1.998%5Ctimes%2010%5E%7B-3%7D)
Like to check? Just add up the charges on both sides and see if they equal each other:)
True
Explanation:
The position of sodium on the periodic table makes the element a solid at room temperature is very correct.
- Sodium is an elements with 11 electrons in its shell.
- It is located in group 1 on the periodic table because it contains an outer valence electron.
- In a free state Na metal, the atoms exhibit metallic bonding.
- Metallic bonding is responsible for the solid nature of this alkali metal at room temperature.
- It is highly reactive because it has just one valence electron.
- Metals are usually found left of the periodic table.
Learn more:
Group 1 brainly.com/question/2154626
#learnwithBrainly
Answer:
C. NaOH(s) + HCl(aaq) rightarrow NaCl(s) + H2O(aq)
Explanation:
A neutralization reaction may be defined as the reaction where an acid when it reacts with some base, the products formed are a salt and water.
Simply, we can write,
acid + base ---> salt + water
Here in option (C),
NaOH is sodium hydroxide is an base
HCl is hydrochloric acid
NaCl is sodium chloride and is the common salt
H20 is water
So, option C). NaOH(s) + HCl(aaq) -----> NaCl(s) + H2O(aq) is a neutralization reaction.
It is inorganic. Organic compound is carbon based.
