Answer:
volume of 
Explanation:
Firstly balance the given chemical equation,
From the given balance equation it is clearly that,
2 mole of Li gives 1 mole of H2 gas
⇔
⇔
⇔
hence
3 mole of Li will give 1.5 mole H2 gas
therefore volume of gas produced from 3 mole Li at 
volume of H2=33.6 litre
Answer:
- <u>The pointer will not be lined up with the zero mark; it will be above the zero mark.</u>
Explanation:
Althoug the list of statements is not provided, you can assure that the pointer will not be lined up with the zero mark, but above the zero mark.
A <em>triple beam balance</em> is very precise instrument, of common use in most labs, used to measure masses. It has three beams. Each beam works for different precisions and mass increments. One beam measures 1 g increments, other beam measures 10 g increments, and the other one 100 g increments.
If you place a mass of 250 grams on the measurement tray, then the weight will be balanced in the beams with 200 grams in the beam that reads increments of 100 g and 50 grams in the beam that reads increments of 10 g. When this is the situation, the weight is completely balanced, and the pointer will be lined up with the zero mark. But this is not the case.
When the rider on the 500 gram beam is set to the 200 gram mark, and the other riders are set to 0 grams, the weight of the mass (250 g) on the tray is greater than the force exerted by the rider on the beam (200 g) and so the tray will be below the level of balance, and the beam will be above the level of balance. The level of balance is indicated when the pointer is lined up with the zero mark.
Answer:
C₁₂H₂₂O₁₁ and CH₃OH
Explanation:
Sucrose and methyl alcohol are nonelectrolytes. They do not ionize or conduct a current in aqueous solution.
HC₂H₃O₂ is a weak electrolyte. It produces only a few ions and is a poor conductor of electricity in aqueous solution.
HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O₂⁻
H₂SO₄ is a strong electrolyte. Its first ionization is complete, so it is a good conductor of electricity in aqueous solution.
H₂SO₄ + H₂O ⟶ H₃O⁺ + HSO₄⁻
Phosphoric acid has 3 pKa values (pKa1=2.1, pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
<span>
</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
