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Ymorist [56]
3 years ago
15

1. Unauthorized persons servicing equipment may jeopardize the safety of operators and

Engineering
2 answers:
emmainna [20.7K]3 years ago
6 0
C. improper signaling. i know cause i just took this test
sergeinik [125]3 years ago
4 0
C. improper signaling
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A 250-pound person would use a Type 1 ladder even if he were carrying a load with him. true or false
serg [7]

Answer:

The answer is <em>False</em>.

Explanation:

Type 1 ladders have a duty rating of 250-pounds. The fact that the person is carrying a load means that they are exceeding 250 pounds.

Type 1A would be best.

In other words, it's better to be safe than sorry.

<em>Source: Ladder Safety PDF </em>

<em />

-Lexi

8 0
3 years ago
Método de Programación lineal utilizado para resolver problemas en teoría de redes?
atroni [7]

Answer:

not sur

Explanation:

5 0
3 years ago
A 5Kw solar system may produce enough energy to power your home. a)-True b)- False
Minchanka [31]

Answer: True

Explanation:

Yes, it is true that 5 Kw solar system may produce enough energy to power your home as, on an average good quality of 5 KW solar system can produced 22 units per day enough to power all home appliances. As, a 5 KW solar system produced energy is basically depends on the three main factor that are:

  • Quality of the solar panel system.
  • Location from where the solar system generated its energy.
  • And also on the positioning of the solar system.
4 0
3 years ago
Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from t
love history [14]

complete question:

Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from the program into your submission. Use if statements and output a message indicating that the expression is True or False.

a = 5,  b = 4,  c = 3,  d = 2 ;

(a <= b + 1 )

(a < b && c > b)

(a >= c || d >= 5)

( !(a > b) )

( b >= a && ! (d < b) )

Answer:

a = 5

b = 4

c = 3  

d = 2

if a <= b + 1 :

       print("True")

else :

      print("False")

if a < b and c > b :

      print("True")

else :

      print("False")

if a >= c or d >= 5:

       print("True")

else :

       print("False")

if not(a > b):

       print("True")

else :

       print("False")

if ( b >= a and not(d < b) ):

       print("True")

else :

      print("False")

Explanation:

I used python to write the code

The equivalent of && in python is and while the equivalent of || is or. The equivalent of !  is not  in python .

I wrote an if statement to print True for each expression if it is actually true and the else statement print False if the expression is actually false.

For example the first expression says if a is less than or equal to b + 1(5). This statement is actually true so the expression will print True. a is 5 and b plus 1 is 5, so a is equal to 5 which is true.

if a < b and c > b :

Both expression must be true for the if statement to print True.  a is not less than b and c is not greater than b so the expression amount to False.

if a >= c or d >= 5:

One expression must be true for the expression to be True. a >= c is true and d >= 5 is false. So the expression amount to True.

not(a > b)

This simply means negate the statement a > b . This gives False.

( b >= a and not(d < b))

b >= a is false

d < b is true

not(d < b) is false

false and false is definitely False

6 0
3 years ago
Describe how the pair-wise summation computation provided below can be changed to find the maximum element of an array. Array ha
Margaret [11]

Answer:

To change the pair-wise summation computation provided  to find a maximum element of an array we; Take two elements to check max element from that and add to the T ARRAY, the same process is then repeated for the next two elements, again we repeat the same process for the next two elements from T array until we get the max element  process going on pair-wise computation

Explanation:

Code written using pair-wise computation to describe how to change the given pair-wise summation computation provided to find the maximum element of an array

The given array element ; (x[0], x[1], x[2], x[3], x[4], x[5], x[6])

IF X[0] > X[1]

T[0]=X[0];

ELSE

T[0]=X[1]

IF X[2] > X[3]

T[1]=X[2];

ELSE

T[1]=X[3];

IF X[4] > X[5]

T[2]=X[4];

ELSE

T[2]=X[5];

T[3]=X[6];

IF T[0] > T[1]

T[4]=T[0];

ELSE

T[4]=T[1]

IF T[2] >T[3]

T[5]=T[2];

ELSE

T[5]=T[3];

IF T[4] > T[5]

MAX=T[4];

ELSE

MAX=T[5]

7 0
4 years ago
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