Answer:
t = 56.6 min
Explanation:
Fick's second law is used to calculate time required for diffusion

where
= 1.15%
= 0.18%
= 0.35%
x = 0.40 mm = 0.0004 n

therefore we ahave
![\frac{1.15-0.35}{1.15- 0.18} = erf[\frac{4\times 10^{-4}}{2\sqrt{1.28\times 10^{-11} t}}]](https://tex.z-dn.net/?f=%5Cfrac%7B1.15-0.35%7D%7B1.15-%200.18%7D%20%3D%20%20erf%5B%5Cfrac%7B4%5Ctimes%2010%5E%7B-4%7D%7D%7B2%5Csqrt%7B1.28%5Ctimes%2010%5E%7B-11%7D%20t%7D%7D%5D)
![0.8247 = erf [\frac{55.90}{\sqrt{t}}] = erf z](https://tex.z-dn.net/?f=0.8247%20%3D%20erf%20%5B%5Cfrac%7B55.90%7D%7B%5Csqrt%7Bt%7D%7D%5D%20%3D%20%20erf%20z)
from error function table we hvae following result
for erf z z
0.8209 0.95
0.8247 x
0.8427 1
therefore

x = 0.959
thus


t = 56.6 min
The answer should be Oc 15
Answer:
Absolute pressure , P(abs)= 433.31 KPa
Explanation:
Given that
Gauge pressure P(gauge)= 50 psi
We know that barometer reads atmospheric pressure
Atmospheric pressure P(atm) = 29.1 inches of Hg
We know that
1 psi = 6.89 KPa
So 50 psi = 6.89 x 50 KPa
P(gauge)= 50 psi =344.72 KPa
We know that
1 inch = 0.0254 m
29.1 inches = 0.739 m
Atmospheric pressure P(atm) = 0.739 m of Hg
We know that density of Hg =
P = ρ g h
P(atm) = 13.6 x 1000 x 9.81 x 0.739 Pa
P(atm) = 13.6 x 9.81 x 0.739 KPa
P(atm) =98.54 KPa
Now
Absolute pressure = Gauge pressure + Atmospheric pressure
P(abs)=P(gauge) + P(atm)
P(abs)= 344.72 KPa + 98.54 KPa
P(abs)= 433.31 KPa
Answer:
A detailed structure diagram
Explanation:
Schematics include blueprints and diagrams and they help people design buildings.
I think D. By pressing gradually