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3 years ago

Good chemistry question

1 answer:

5 0

Compared to the charge and mass of a proton an electron has......

A proton has approximately the same mass as..........

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Which step of scientific inquiry involves organizing and interpreting the data?

elena-14-01-66 [18.8K]

b. Analysis. In the analysis step, you organize and interpret your data to see if they support your hypothesis.

a. Experimentation is <em>incorrect</em> because this is the step in which you do experiments to test if your prediction is accurate.

c. Conclusion is <em>incorrect</em> because a conclusion is a decision you make to accept or reject your hypothesis.

d. Hypothesis is <em>incorrect</em> because a hypothesis is a proposed explanation for why something happens.

8 0

2 years ago

Express the following number in scientific notation: 0.000000675.

tekilochka [14]

There are 7 digits from decimal to 1st digit, and it's coming from right, so exponent will be in negative 7

In short, Your Answer would be: Option C) <span>6.75 × 10-7
</span>
Hope this helps!

6 0

3 years ago

An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes t

mihalych1998 [28]

Answer:

The answer is "11.07 g".

Explanation:

Isoamyl alcohol is a reagent restriction

Isoamyl alcohol Moles:

$= \frac{7.5}{88.15} \\\\ =0.085$

Moles only with the shape of isoamyl acetate are equivalent to numbers.

Isoamyl acetate grams:

$= 0.085 \times 130.19\\\\ = 11.07 \ g$

3 0

2 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m

Bond [772]

Answer:

$m_{H_2O}=4.86gH_2O$

Explanation:

Hello,

In this case, the described chemical reaction is:

$C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O$

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

$n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6$

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

$n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6$

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

$m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O$

Best regards.

3 0

3 years ago

HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?

Snezhnost [94]

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 40 g

volume = 10 mL

The density of the object is

$density = \frac{40}{10} = 4 \\$

We have the final answer as

Hope this helps you

5 0

2 years ago