Density=mass/volume
Volume= 5.05 x 2.55 x 1.25 = 16.096875 cm^3
Density= 143.584/16.096875
= 8.919992235 g/cm^3
We can tell which acid which have the highest percent ionization on the basis of pH value.
<h3>What is percent ionization?</h3>
The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.
If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.
Hence acids with high pH value will show highest percent ionization.
To know more about percent ionization, visit the below link:
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Answer:
the properties of three undiscovered elements is the correct answer.
Explanation:
After he completed his work Mendeleev predicted the properties of the undiscovered elements.
In the year 1871, Dmitri Mendeleev predicted the detailed existence and the properties of the three elements that are undiscovered and he gained tremendous fame.
He left the gap in the table to put the elements which are not identified at that time and by glancing at the physical and chemical properties of an element next to the gap, Mendeleev could predict the properties of the not discovered elements.
Answer : The value of
for
is
.
Solution : Given,
Solubility of
in water = 
The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.
The equilibrium equation is,

Initially - 0 0
At equilibrium - s s
The Solubility product will be equal to,
![K_{sp}=[Ba^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)

![[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%3D%5BCO%5E%7B2-%7D_3%5D%3Ds%3D4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
Now put all the given values in this expression, we get the value of solubility constant.

Therefore, the value of
for
is
.
first find the atomic weight of CH3 which would be
atomic weight: 12.011 (3×1.008) = 36.32 g/mol
then find the moles in the given mass
36.32 ÷ 45.7 = 0.794
I HOPE I'M NOT WRONG I HAVENT DONE CHEM IN SO LONG