What is it called when grouping items that are alike in some way
1 answer:
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Explanation:
During titration of oxalic acid and in acid medium to reaction is extremely slow. Since
is acting as a self indicator the colour disappears after less than 30s even after approaching equivalent point. So the reaction mixture is heated to approximately 70–
(just before it starts boiling) and the titration is started. This helps in initiating the reaction via supplying the necessary activation energy of the reaction. Secondly the heat helps to decompose
complex which forms as a result of local excess of
.the complex is unstable above
and the
formed as a result catalyses the rest of the reaction. Thirdly the temp should never exceed the range given as oxalic acid will decompose above this temp to
The question is incomplete, the complete question is shown in the image attached to this answer.
Answer:
139.13
Explanation:
The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.
We obtain the relative atomic mass of Likhitium as follows;
(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)
61.7 + 73.2 + 0.7 + 3.53 = 139.13
Hence the relative abundance of Likhitium is 139.13
Taking into account the stoicionetry reaction and the definition of limiting reagent, Li₂O is present in limiting quantities.
The balanced reaction is:
Li₂O + H₂O → 2 LiOH
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Li₂O: 1 mole
- H₂O: 1 mole
- LiOH: 2 moles
The molar mass of each compound is:
- Li₂O: 29.88 g/mole
- H₂O: 18 g/mole
- LiOH: 23.95 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Li₂O: 1 mole× 29.88 g/mole= 29.88 g
- H₂O: 1 mole× 18 g/mole= 18 g
- LiOH: 2 moles× 23.95 g/mole= 47.9 g
On the other side, the limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 18 grams of H₂O reacts with 29.88 grams of Li₂O, 106 grams of H₂O react with how much mass of Li₂O?
mass of Li₂O= 175.96 grams
But 175.96 grams of Li₂O are not available, 195 grams are available. Since you have less moles than you need to react with 106 grams of H₂O, Li₂O will be the limiting reagent.
Finally, Li₂O is present in limiting quantities.
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