1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
1 year ago
10

Solve the following question

Chemistry
1 answer:
Andrew [12]1 year ago
4 0

Answer:

140. J/g*K

Explanation:

To find the specific heat capacity, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/mole*K)

-----> ΔT = change in temperature (K)

Before you can use the equation above, you need to (1) convert kg to grams, then (2) convert grams to moles (via molar mass), and then (3) convert Celsius to Kelvin. The final answer should have 3 significant figures.

1.11 kg C₄H₈O₂ x 1,000 = 1110 g

Molar Mass (C₄H₈O₂): 4(12.01 g/mol) + 8(1.008 g/mol) + 2(16.00 g/mol)

Molar Mass (C₄H₈O₂): 88.104 g/mol

1110 grams C₄H₈O₂                1 mole
------------------------------  x  -------------------------  =  12.6 moles C₄H₈O₂
                                           88.104 grams

34.5 °C + 273 = 307.5 K

52.3 °C + 273 = 325.3 K

Q = mcΔT                                                                   <----- Equation

3.14 x 10⁴ J = (12.6 moles)c(325.3 K - 307.5 K)         <----- Insert values

3.14 x 10⁴ J = (12.6 moles)c(17.8)                                <----- Subtract

3.14 x 10⁴ J = (224.28)c                                 <----- Multiply 12.6 and 17.8

140. = c                                                         <----- Divide both sides by 224.28

**this answer may be slightly off due to using different molar masses/Kelvin conversions**

You might be interested in
At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?
DedPeter [7]

Answer:

447,25k

Explanation:

According to the ideal gas law

PV=nRT

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

T=\frac{PV}{nR}\\ \\T=\frac{12,3L.1,95atm}{0,654mol.0,082(L.atm/K.mol)}\\ \\T=447,25K

3 0
3 years ago
You have an unknown quantity of oxygen at a pressure of 2.2 atam, a volume of 21 liters and a temperature of 87 Celsius. How man
laila [671]

<span>Let's assume that the oxygen gas has ideal gas behavior. 
Then we can use ideal gas formula,
      PV = nRT</span>


Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

<span>
P = 2.2 atm = 222915 Pa
V = 21 L = 21 x 10</span>⁻³ m³

n = ?

R = 8.314 J mol⁻¹ K⁻¹

<span> T = 87 °C = 360 K

By substitution,
</span>222915 Pa x 21 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻<span>¹ x 360 K
                                       n = 1.56</span><span> mol</span>

<span>
Hence, 1.56 moles of the oxygen gas are </span><span>left for you to breath.</span><span>
</span>
6 0
3 years ago
The substances below are listed by increasing specific heat capacity value. Starting at 30.0 °C, they each absorb 100 kJ of ther
timama [110]

Answer:

Silver, 0.239 J/(g °C)

Explanation:

  • The heat change is related to specific heat as given by the formula;

Heat change = mass of substance × specific heat × change in temperature

  • Therefore; considering same amount of substance or equal masses and have the same initial temperature.
  • The change in temperature will be inversely proportional to the specific heat.
  • Therefore; the higher the specific heat lower the temperature change.
  • Hence,  the change in temperature will be highest for the substance with the lowest specific heat.

Therefore; the one that will increase in temperature the most is Silver

7 0
3 years ago
If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
8 0
3 years ago
Each chemical element has an atomic number and a mass number. the atomic number refers to the number of ___________________the e
creativ13 [48]
The atomic number tells us the number of protons and electrons.
The atomic mass tells us the weight of the nucleus, which is the amount of protons and neutrons
5 0
3 years ago
Other questions:
  • Using the equation PCl5(g)=PCl3(g)+Cl2(g), if PCl5 is removed, what will the equilibrium shift?
    9·1 answer
  • Which of the following would you expect to form an ionic bond when combined?
    12·1 answer
  • Match the vocabulary terms to their definitions.
    14·1 answer
  • Contrast How are photosynthesis and cellular respiration different?
    6·1 answer
  • Determine the specific heat of a material if a 35-9 sample absorbed 96 ) as it was heated from 293 Kto 313 K.
    11·1 answer
  • What is a hypothesis?
    7·1 answer
  • 14. Carbon-14 emits beta radiation and decays with a half-life (t) of 5730 years. Assume
    14·1 answer
  • 3. How many molecules of CO2 are in 6.0 g of CO2?
    5·1 answer
  • In a balanced equation, the number of each type of atom on the reactant side ____________ the number of each type of atom on the
    14·1 answer
  • Can bees really fly if so why
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!