Answer:

Explanation:
<u>Accelerated Motion
</u>
When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

where a is the acceleration, and vo is the initial speed
.
The train has two different types of motion. It first starts from rest and has a constant acceleration of
for 182 seconds. Then it brakes with a constant acceleration of
until it comes to a stop. We need to find the total distance traveled.
The equation for the distance is

Our data is

Let's compute the first distance X1


Now, we find the speed at the end of the first period of time


That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0



Computing the second distance


The total distance is



Answer:
0.12m/s
Explanation:
v=λf
Given that, λ = 12cm = 0.12m
T = 1second
(A period T is the time required for one complete cycle of vibration to pass a given point)
frequency 'f' is unknown but we can get frequency from f = 1/T = 1/1 = 1Hz
therefore, v= 0.12 × 1 = 0.12m/s
The total distance you would have covered is equivalent to going around the earth 22 times.
<h3>
Total distance traveled</h3>
The total distance traveled at a given speed and time of motion is calculated as follows;
Distance = speed x time

<h3>Distance round the Earth</h3>
The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles
<h3>Number of times round the earth</h3>

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.
Learn more about distance here: brainly.com/question/17273444
Answer:

Explanation:
Relevant Data provided
Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2
Distance which indicates d = 1.50 x 10^-3 m
Voltage which indicates V = 12 V
According to the requirement, the computation of value of its capacitance is shown below:-


= 
Therefore for computing the capacitance we simply applied the above formula.
At the begging nothing is happening, but when you push it, it gains speed that is why the end of a ramp is faster.