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3 years ago

8

Consider the following two well-mixed, isothermal gas-phase batch reactors for the elementary and irreversible decomposition of

A to B given by the following chemical equation: A k −−→ 2 B (1) In reactor 1, the reactor volume is held constant (reactor pressure therefore changes). In reactor 2, the reactor pressure is held constant (reactor volume therefore changes). Both reactors are charged with pure A at 2.0 atm, A and B are considered ideal gases, and k = 0.35 min−1 .
(a) What is the fractional decrease in the concentration of A in reactors 1 and 2 after five minutes?
(b) What is the total molar conversion of A in reactors 1 and 2 after five minutes?

1 answer:

Nesterboy [21]3 years ago

8 0

Answer:

attached below

Explanation:

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Technician A says that a special wire brush is needed if it will be rotated at high rpm. Technician B says that some wire brushe

Charra [1.4K]

Answer:

Option C

Both A and B

Explanation:

Both technicians are right about what they say about wire brushes. wire brushes are usually made up of steel wire bristles. however, when high RPMs are involved, it is better to get some special types of brushes for that purpose. This is because the heat generated at high RPMs is great, and most times, damages the brush after prolonged use if it is not specially built for such speeds.

In addition that, some wire brushes have plastic hubs which help support the bristles and is usually attached to the motor.

Considering these, we can say that the Two technicians are right

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4 years ago

4.A compression spring has a diameter of 0.67 in and a coil diameter of 0.067 in, with 30 total coils. The spring is to be made

Akimi4 [234]

Answer:

Fatigue factor of safety is 2.0267

Explanation:

Solution is attached below.

4 0

4 years ago

Develop a chase plan that matches the forecast and compute the total cost of your plan. (Negative amounts should be indicated by

vladimir2022 [97]

Answer:

The answer for the question :

"Develop a chase plan that matches the forecast and compute the total cost of your plan. (Negative amounts should be indicated by a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Omit the "$" sign in your response.)"

is explained in the attachment.

Explanation:

4 0

3 years ago

Air enters a 200 mm diameter adiabatic nozzle at 195 deg C, 500 kPa and 100 m/s. It exits at 85 kPa. If the exit diameter is 158

ahrayia [7]

Answer:

$v_2 = 160.23 m/s$

$T_2 = 475.797 k$

Explanation:

given data:

Diameter = $d_1 = 200mm$

$t_1 =195 degree$

$p_1 =500 kPa$

$v_1 = 100m/s$

$p_2 = 85kPa$

$d_2 = 158mm$

from continuity equation

$A_1v_1 = A_2v_2$

$v_2 = \frac{\frac{\pi}{4}d_1^2 v_1^2}{\frac{\pi}{4}d_2^2}$

$v_2 = \frac{d_2v_1}{d_2^2}$

$v_2 = [\frac{d_1}{d_2}]^2 v_1$

$= [\frac{0.200}{0.158}]^2 \times 100$

$v_2 = 160.23 m/s$

by energy flow equation

$h_1 + \frac{v_1^2}{2} +gz_1 +q =h_2 + \frac{v_2^2}{2} +gz_2 +w$

$z_1 =z_2$ and q =0, w =0 for nozzle

therefore we have

$h_1 -h_2 =\frac{v_1^2}{2} -\frac{v_2^2}{2}$

$dh = \frac{1}{2} (v_1^2 -v_2^2)$

but we know dh = Cp dt

hence our equation become

$Cp(T_2 -T_1) = \frac{1}{2} (v_1^2 -v_2^2)$

$Cp (T_2 -T_1) = 7836.94$

$(T_2 -T_1) = \frac{7836.94}{1.005*10^3}$

$(T_2 -T_1) = 7.797$

$T_2 = 7.797 +468 = 475.797 k$

8 0

3 years ago

A helical compression spring is to be made of oil-tempered wire, d, of diameter 1–mm with a spring index of C = 10. The spring i

BaLLatris [955]

Question

Determine the minimum hole diameter for the spring to operate in

Answer:

11 mm

Explanation:

Mean spring coil diameter is given from the following relationship

D=cd where C is spring index and d is the diameter of oil-tempered wire

By substitution

D=10*1 mm=10 mm

To find the outer diameter, we add the d to D hence getting the minimum hole diameter as

$D_o= D+d= 10 mm+1 mm= 11 mm$

5 0

3 years ago