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3 years ago

How many moles of h2 gas would be contained in 4.00 of the gas at 202.6KPa and 127c?

Physics

1 answer:

JulsSmile [24]3 years ago

4 0

Answer : The volume of one mole of gas is dependent of temperature and pressure.

Explanation:

At 0oCand1atm one mole of an ideal gas would be ≈22.4L, which is the same as 22.4dm3

If you double the pressure, the same amount (mole) of gas would take up only half the space.

If the temperature changes (and pressure stays constant), the gas will expand or contract by about 1%/3o.

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Which of the following choices describes the type of image formed by a plane mirror?

Aleks04 [339]

Virtual upright and the same size

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4 years ago

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A wedge with a mechanical advantage of 0.78 is used to raise a house corner from its foundation. If the output force is 7500 N,

Zigmanuir [339]

Answer:

5850

Explanation:

MA = Force out/ Force in

.78 = out/ 7500

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3 years ago

A block lies on a horizontal frictionless surface and

zhenek [66]

Answer:

0.1 m

Explanation:

F = Force exerted on spring = 3 N

k = Spring constant = 60 N/m

x = Displacement of the block

As the energy of the system is conserved we have

$Fx=\dfrac{1}{2}kx^2$

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$\\\Rightarrow x=\dfrac{2\times 3}{60}$

$\\\Rightarrow x=0.1\ m$

The position of the block is 0.1 from the initial position.

6 0

3 years ago

A wave front has the form of a

podryga [215]

Your answer is "surface of a sphere"

Hope this helps.

3 0

3 years ago

A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision

Nimfa-mama [501]

Answer:

Δ KE = 249158.6 kJ

Explanation:

given data

Truck mass M = 1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum that is express as

Mu = (M+m) V .......................1

put here value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy will be here

Δ KE = $\frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2$ .................2

put here value and we get

Δ KE = $\frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2$

solve it we get

Δ KE = 249158.6 kJ

6 0

3 years ago