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-BARSIC- [3]
3 years ago
9

In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?

Physics
1 answer:
lidiya [134]3 years ago
5 0

Answer: This is the orbit (of the moon around Earth).

An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

You might be interested in
8 The diagram shows four identical spheres placed between two wooden blocks on a ruler.
enyata [817]

The diameter of the sphere is 2cm.

<h3>How to calculate the diameter?</h3>

From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.

Therefore, the length will be:

= 12 - 4.

= 8cm

The diameter of one sphere will be:

= Length / 4

= 8/4

= 2

Therefore, the diameter of the sphere is 2cm.

Note that the second question wasn't found online.

Learn more about diameter on:

brainly.com/question/358744

#SPJ1

8 0
2 years ago
If one object is 103 km away and a second object is 106 km away, one could say that the second object is _____ times further awa
vaieri [72.5K]

Answer:

1.03

Explanation:

\frac{object_{second}}{object_{first}} = \frac{106}{103} = 1.02912621359

Round to three significant digits

1.03

7 0
3 years ago
Which state of matter has the MOST energy?
Nonamiya [84]

Answer:

Gas

Explanation:

The gas state of matter has the most energy because of how freely the molecules move

4 0
3 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

Learn more about circular motion:

brainly.com/question/2562955  

brainly.com/question/6372960  

#LearnwithBrainly

8 0
3 years ago
If the escalator pulls you up a slope of 30.0o​ ​ and moves with a velocity of 3.10m/s. What is the vertical component of your v
ioda

Answer:

1.55\ \text{m/s}

2.68\ \text{m/s}

Explanation:

v = Velocity of the elevator = 3.1 m/s

\theta = Angle of the slope = 30^{\circ}

Vertical component is given by

v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^{\circ}\\\Rightarrow v_y=1.55\ \text{m/s}

The vertical component of the velocity is 1.55\ \text{m/s}.

Horizontal component is given by

v_x=v\cos\theta\\\Rightarrow v_x=3.1\times \cos30^{\circ}\\\Rightarrow v_x=2.68\ \text{m/s}

The horizontal component of the velocity is 2.68\ \text{m/s}.

8 0
3 years ago
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