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3 years ago

In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?

Physics

1 answer:

lidiya [134]3 years ago

5 0

Answer: This is the orbit (of the moon around Earth).

An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

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QUESTION:

vampirchik [111]

Answer:

I don't know why you are asking me?

5 0

3 years ago

A block is being pulled upward along an inclined surface at a constant speed. Which of the following statements is correct? Grou

Alex17521 [72]

Answer:The net force on the block is zero.

Explanation:

Given

Block is being pulled upward along an inclined surface at a constant speed

As speed is constant and moved in a straight line along the plane therefore its velocity is also constant .

and change in velocity is equal to acceleration therefore acceleration is zero here i.e. net force is zero acting on the body.

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3 years ago

A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel

trasher [3.6K]

Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2$

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s$

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

$1\ mile=1609.34\ m$

$1\ h=3600\ seconds$

$18.03\times \frac{3600}{1609.34}=40.33\ mph$

Speed of the boat by when it will hit the dock is 40.33 mph

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m$

The distance at which the boat will have to start decelerating is 312.5 m

5 0

3 years ago

Select the correct answer.

kipiarov [429]

Answer:

Explanation:

If the object is moving at a constant speed, the object isn't accelerating as the velocity doesn't change.

5 0

3 years ago

Bx = -1.33 m and By = 2.81 m<br> Find the magnitude of the<br> vector.

NISA [10]

Answer:

Explanation:

The formula for the magnitude of a vector is

$B_{mag}=\sqrt{(-1.33)^2+(2.81)^2}$ and then round to the hundredths place:

3.11 m. Since we are in Q2, we can also find the direction of this vector:

$tan^{-1}(\frac{2.81}{-1.33})=-64.7$ but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3

3 0

3 years ago