Answer:
y = y₀ (1 - ½ g y₀ / v²)
Explanation:
This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i
y = y₀ + v₀ t - ½ g t²
y = y₀ - ½ g t²
for the ball thrown from the ground with initial velocity v₀₂ = v
y₂ = y₀₂ + v₀₂ t - ½ g t²
in this case y₀ = 0
y₂2 = v t - ½ g t²
at the point where the two balls meet, they have the same height
y = y₂
y₀ - ½ g t² = vt - ½ g t²
y₀i = v t
t = y₀ / v
since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height
y = y₀ - ½ g t²
y = y₀ - ½ g (y₀ / v)²
y = y₀ - ½ g y₀² / v²
y = y₀ (1 - ½ g y₀ / v²)
with this expression we can find the meeting point of the two balls
Answer:
Explanation:
The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:
, where 
is the mass of the basketball and 
is the change in velocity.
Since the basketball is changing direction, its total change in velocity is:
.
Therefore, the basketball's change in momentum is:
.
Thus, the impulse on the basketball is 
(two significant figures).
Try dividing 347 by the molecular mass of Mg added to that of Cl2.
Answer:
charge = electrons + protons
=92+92
=184
Typebars
Turbocars
Teacups
Teapoys
Tourneys
Toecaps
Trepangs
Tabourers
Trouncers
Troupers
Terraces
Trances
Turbans
Toupees
Toucans
Sorry if this is not what you want me to do and I just threw a bunch of words at you.
