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Illusion [34]
3 years ago
11

Which type of rock is Most likely to form because of high heat and pressure

Chemistry
2 answers:
vekshin13 years ago
6 0

Answer:

Metamorphic rock

Explanation:

valentina_108 [34]3 years ago
3 0

Answer:

metamorphic

Explanation:

just took the test

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____________ is a point source of water pollution; _____________ is a nonpoint source of water pollution.
Deffense [45]

Answer:

good afternoon

Explanation:

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6 0
2 years ago
What is the formal charge on the hydrogen atom in hf?
stepladder [879]

The formal charge of H = +1, because F in compounds can have only -1.

4 0
2 years ago
Read 2 more answers
Which element is least metallic?<br><br> zinc<br> iron<br> cadmium<br> silver
skad [1K]
Cadmium is less metalic
5 0
3 years ago
Read 2 more answers
1. A sample of polystyrene is found to have a number-average molar mass of 89,440 g mol−1 . Neglecting contributions from end gr
Snowcat [4.5K]

Answer:

The weight-average molar mass of polystyrene is 134,160 g/mol.

Explanation:

Molar mass of the monomer styrene , C_8H_8, M=104 g/mol

Given , number average molar mass of the polymer , M'= 89,440 g/mol

Degree of polymerization = n

n=\frac{M'}{M}=\frac{89,440 g/mol}{104 g/mol}=860

The weight-average molar mass = M_{avg}=?

Molar mass dispersity is ratio of weight-average molar mass to the number average molar mass of the polymer.

\text{Molar mass dispersity}=\frac{M_{avg}}{M'}

1.5=\frac{M_{avg}}{89,440 g/mol}

M_{avg}=89,440 g/mol\times 1.5 = 134,160 g/mol

The weight-average molar mass of polystyrene is 134,160 g/mol.

8 0
2 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
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