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lilavasa [31]
3 years ago
7

If a strong base, like NaOH, is added to a strong acid, like HCl, the pH of the resultant solution will _________. A.) Go up B.)

Go down C.) Stay the same
Chemistry
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

B.) Go down

Explanation:

Hello,

In this case, a strong base like NaOH has a high pH based on the scale wherein 7 is neutral, above 7 is basic and below 7 is acid. In such a way, by adding an acid, having a low pH, once it is added, the pH will go down until the equivalence point, which for strong base and strong acid should be 7.

Best regards.

Ivahew [28]3 years ago
7 0

Answer:

B) Go down

Explanation:

pH is defined as -log [H⁺], that means when concentration of H⁺ increases the pH decreases and when concentration of H⁺ decreases, pH increases.

When a strong acid as HCl is added to a solution, it is dissolved, thus:

HCl → H⁺ + Cl⁻

Thus, <em>addition of a strong acid decreases pH because concentration of H⁺ increases.</em>

<em />

Right answer is:

<em>B) Go down</em>

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Fiesta28 [93]

Complete Question

Questions Diagram is attached below

Answer:

*  W=1142.86Joule

*  Q=997.7J

*  H=2140.5J

Explanation:

From the question we are told that:

Temperature T=337K

Pressure P=(60-55)Pa*10^5

VolumeV=(1.6-1.4)m^3*10^{-3}

Generally the equation for gas Constant is mathematically given by

\frac{P_2}{P_1}=\frac{V_1}{V_2}^n

 \frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n

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Therefore

Work-done

 W=\int{pdv}

 W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}

 W=1142.86Joule

Generally the equation for internal energy is mathematically given by

 Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}

 Q=997.7J

Therefore

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 H=2140.5J

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