Question

Calculate the energy of an electron in the n = 2 level of a hydrogen atom.

Answer 1

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and $n^{th}$ orbit of an atom is as follows.

$E = - \frac{13.6}{n^{2}} eV$

Substitute the values into above formula as follows.

$E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV$

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.