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2 years ago

Calculate the energy of an electron in the n = 2 level of a hydrogen atom.

Chemistry

1 answer:

ANEK [815]2 years ago

5 0

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and $n^{th}$ orbit of an atom is as follows.

$E = - \frac{13.6}{n^{2}} eV$

Substitute the values into above formula as follows.

$E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV$

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

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Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:

Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

$\frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} )$ ,

where λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from $n_1$ to $n_2$ and $R_h$ = 109677 is the Rydberg Constant. Here $n_1$ and $n_2$ represents the transitions.

(a) $n_1$ =2 to $n_2$ = infinity

$\frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2} )$ = 109677/4 [since 1/infinity = 0] Therefore, $\lambda$ = 4 / 109677 = 0.00003647 m

(b) $n_1$ =4 to $n_2$ = 20

$\frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2} )$ = 6580.62

Therefore, $\lambda$ = 1 / 6580.62 = 0.000152 m

(c) $n_1$ =3 to $n_2$ = 10

$\frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2} )$ = 11089.56

Therefore, $\lambda$ = 1 / 11089.56 = 0.00009 m

(d) $n_1$ =2 to $n_2$ = 1

$\frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2} )$ = - 82257.75

Therefore, $\lambda$ = 1 /82257.75 = - 0.0000121 m

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0

1 year ago

How many Joules must be removed to condense 150.0g of steam at 100.0 degrees Celsius to water at 100.0 degrees celcius

Elina [12.6K]

Answer:

339kJ

Explanation:

Given parameters:

Mass of steam = 150g = 0.15kg

Initial temperature of steam = 100°C

Final temperature of water = 100°C

Unknown:

Quantity of heat that must be removed to condense the steam = ?

Solution:

The heat involved here is a latent heat because there is no change temperature. The process is just a phase change.

H = mL

m is the mass

L is the latent heat of vaporization = 2,260 kJ/kg

Insert the parameters and solve;

H = 0.15kg x 2,260 kJ/kg

H = 339kJ

7 0

2 years ago

A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.

Readme [11.4K]

Answer: 1741289L

Explanation:

1 gallon = 3.78541 L

4.6×10^5 gallons = 4.6×10^5 x 3.78541 = 1741289L

6 0

2 years ago

Read 2 more answers

What method is used for chaff from grain<br>

Marta_Voda [28]

Answer:

Winnowing

Explanation:

Wind blows the lighter(in terms of mass) chaff from the whole grains,which are heavier(in terms of mass)

4 0

1 year ago

20 POINTS!!

Alenkinab [10]

Answer:

1. molarity is = 0.1174

2. molarity is = 9.3

3. molarity is =0.009392

Explanation:

Q#1.

mass of sucrose is 14.07g

molar mass of sucrose is 342 3g/mol

so, 14.07x1/342.3 = 0.0411

now the volume is of water is 0.35

so, 0.0411/0.35 = 0.1174

Q#2.

concentration is 4.5

so, 4.5x1/1000= 0.0045

then, 0.0411/0.0045 = 9.13

Q#3.

M1M1=M2M2

molarity of the same sucrose is 0.1174

so, diluted in 40mL

and the volumetric flask is 500mL

so, 0.1174x40/500= 0.009392

8 0

2 years ago