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oee [108]
3 years ago
12

A mixture of 2.0 moles of H2, 2.0 moles of NH4, 4.0 moles of CO2, and 5.0 moles of

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

0.01125

Explanation:

:b

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Non-living factors in an ecosystem are ______.
mash [69]

Answer:

B. abiotic

Explanation:

in biology and ecology, abiotic components or abiotic factors are non living chemical and physical parts of the environment that affect living organisms and the functioning of ecosystems.

5 0
2 years ago
Help me, it’s pretty easy science moon stuff !
trasher [3.6K]
Hello :)
Based on the information I received reading the picture, the answer should be “B”

Explanation: if I am wrong I’m very sorry. But that should be the answer
8 0
2 years ago
Read 2 more answers
It is logical to conclude that water cannot dissolve vegetable oil because the oil is
Gekata [30.6K]
In chemistry, there is a common note that says, "Like dissolves like".

This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances. 

Polarity of the substance depends primarily on the type of bond and the difference in electronegativity. 

Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical. 
3 0
3 years ago
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You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

6 0
3 years ago
A solution that cannot dissolve more and already has a large amount of dissolved is
Nikitich [7]

Answer:

Saturated Solution

Explanation:

Happy to help

Pls mark as Brainliest.

8 0
3 years ago
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