A mixture of 2.0 moles of H2, 2.0 moles of NH4, 4.0 moles of CO2, and 5.0 moles of
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Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Answer:
Acid: HCl(aq), conjugate base: Cl⁻(aq)
Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)
The rewrite reaction is shown below.
Explanation:
The acid compound is the one that loses an H⁺, and the compound formed when it happens is its conjugate base. The base compound is the acceptor of H⁺, and its conjugate acid is the compound formed (Brosted-Lowry theory).
So, the acid-base pairs are:
Acid: HCl(aq), conjugate base: Cl⁻(aq)
Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)
The TUMS® is an antacid, so it intends to reduce the concentration of the strong acid HCl. So, the forward reaction is favored. It can be represented with the forward arrow larger than the reversible arrow, as shown in the image below.
