how many grams of molecular oxygen (O2) is produced from 13.8 grams of calcium chlorate (Ca(ClO3)2)in the following chemical rea
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Answer:
His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.
Explanation:
The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.
Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.
Suppose the mass of the solute is m.
Originally, the density is =
Now after adding extra 10 mL , the density becomes .
Therefore,
So the density decreases when we add more solution.
<u>Answer:</u> The heat required will be 58.604 kJ.
<u>Explanation: </u>
To calculate the amount of heat required, we use the formula:
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.