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Firdavs [7]
3 years ago
12

how many grams of molecular oxygen (O2) is produced from 13.8 grams of calcium chlorate (Ca(ClO3)2)in the following chemical rea

ction?Ca(ClO3)2→CaCl2+ 3O2
Chemistry
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

6.72 g

Explanation:

Given data:

Mass of calcium chlorate = 13.8 g

Mass of oxygen produced = ?

Solution:

Chemical equation:

Ca(ClO₃)₂        →      CaCl₂ + 3O₂

Number of moles of calcium chlorate:

Number of moles = mass / molar mass

Number of moles = 13.8 g/ 206.98 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of oxygen and  calcium chlorate.

                 Ca(ClO₃)₂         :            O₂

                      1                   :              3

                    0.07               :            3×0.07=0.21 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.21 mol × 32 g/mol

Mass = 6.72 g

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What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
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Answer:

The answer to your question is C₂HO₃

Explanation:

Data

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Carbon = 19.36%

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Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

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