Answer:
298,220 N
Explanation:
Let the force on car three is T_23-T_34
Since net force= ma
from newton's second law we have
T_23-T_34 = ma
therefore,
T_23-T_34 = 37000×0.62
T_23= 22940+T_34
now, we need to calculate
T_34
Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2
F= ma
So, F= 12×37000×0.62= 22940×12= 275280 N
T_23 =22940+T_34= 22940+ 275280= 298,220 N
therefore, the tension in the coupling between the second and third cars
= 298,220 N
During cellular respiration, our bodies take glucose molecules and breaks the bonds holding the molecules together. When these bonds are broken, the chemical energy stored in these bonds are released and used to make ATP molecules, a form of useable energy for us.
Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North
A.draw in the forces .Use the scale 1cm =10n of force
Answer: a good level of body fat can be found using your weight and height as a reference.
Explanation:
