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EastWind [94]
3 years ago
7

A car travels at 60 miles per hour. How much time does it take the car to travel 30 miles? Select one: a. 1 hour b. 1/2 hour c.

3/4 hour d. 2 hours
Physics
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

b.t=\frac{1}{2} hour

Explanation:

Conceptual analysis

The average velocity (v) is defined as the ratio between the displacement (d) that a body performed and the total time (t) that the displacement lasted and is calculated using the following formula:

v=\frac{d}{t}Formula (1)

v: velocity

d: Displacement

t: Time

Known data:

v=60 \frac{miles}{hour}

d = 30 miles

Problem development

We replace data in formula (1):

60\frac{miles}{hour}=\frac{30miles}{t}

t= \frac{30 miles}{60\frac{miles}{hour} }

t=\frac{1}{2} hour

andreev551 [17]3 years ago
4 0
The car is traveling at 60 miles per hour. Theoretically, at this pace, It'll take (B.), 1/2 an hour.


Brainliest?


Hope I helped! ^-^
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The concrete slab of a basement is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are nominally 17°C and
mina [271]

Answer:

\frac{dQ}{dt}= 4312 W

Explanation:

As we know that base of the slab is given as

A = 11 \times 8

A = 88 m^2

now we know that rate of heat transfer is given as

\frac{dQ}{dt} = \frac{kA}{x} (T_2 - T_1)

here we know that

k = 1.4 W/m k

Also we have

x =0.20

\frac{dQ}{dt} = \frac{1.4(88)}{0.20}(17 - 10)

\frac{dQ}{dt}= 4312 W

7 0
3 years ago
The portion of earth underneath the crust containing the asthenosphere and the mesosphere is the
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6 0
3 years ago
You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
Andru [333]

Answer:

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

v = velocity of the ball at time t.

Placing the origin at the throwing point, y0 = 0.

Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t²     (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Have a nice day!

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