Question

A gas has an initial volume of 3.0 L with a pressure of 0.62 atm. What will be the new pressure if the volume changed to 1.0 L?

Answer 1

Answer:

The new pressure will be 1.86 atm.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way pressure and volume are related, determining Boyle's law.

Boyle's law says that at constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts:

P*V=k

To determine the change in pressure or pressure during a transformation to constant pressure, the following expression is applied:

P1*V1=P2*V2

In this case:

• P1= 0.62 atm
• V1= 3 L
• P2= ?
• V2= 1 L

Replacing:

0.62 atm* 3L= P2* 1 L

Solving:

$P2=\frac{0.62 atm*3L}{1L}$

P2= 1.86 atm

The new pressure will be 1.86 atm.