- Sedimentation and Decantation is the process of setting of solid particles from a liquid either to produce a concentrated slurry or to clarify a liquid containing solid particles . The solid must not be mixed with liquid. For example- sand insoluble in water
- Sublimation - In this process solid phase is directly transformed into vapour form without passing through liquid phase.This method is used in the purification of those substances which have sublimation property. At first the mixture should be sublimed before dissolution in liquid.
- EX- Iodine , naphthalene, ammonium chloride etc. Here, NH4Cl is seperated by sublimation.
- Evaporation is a technique used to separate out homogeneous mixtures where there is one or more dissolved salts. The process convert the liquid components from the solid components. The process typically involves heating the mixture until no more liquid remains.
- so, now by evaporation of the liquid solvent we finally get the salt that was dissolved in it that is NaCl.
To know more about Sedimentation visit :brainly.com/question/22443465
#SPJ4
One way can be forming an ionic bond
Second way can be forming covalent bond
And finally, the third way could be forming Co-ordinate bond
Well, depending on the charge, it could be Cu; if it has a charge of 2+
Answer:
Benzaldehyde is less electrophilic than acetaldehyde
Explanation:
Electrophilicity of carbonyl carbon depends on it's positive charge density.
In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.
In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.
We know that resonating effect are more stronger than inductive effect.
Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.
So, benzaldehyde is less electrophilic than acetaldehyde.
Resonating effect of phenyl group has been shown below.
