Answer:
Argon
Explanation:
The element that would most likely be a good substitute for neon is "argon".
These two elements belong to the noble gases in Group 18(8A) of the Periodic Table. They are inert gases - they do not react chemically with other substances.
Argon, as an inert gas is often used whenever an inert atmosphere is needed. Argon is used in incandescent light bulbs. It is used to stop oxygen from corroding the filament. It is also used by welders to protect weld area.
Argon is a good substitute for neon in this context because they possess some physical properties which are similar.
Waves propagating through material medium the amplitude of the waves decides the intensity of the waves as intensity is directly proportional to the square of its amplitude.
The heavy atom count of a casein molecule is 143 I believe
Answer : The correct option is, (B) bent, 2, and 
Explanation :
Formula used :
![\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
The given molecule is, 
![\text{Number of electrons}=\frac{1}{2}\times [5+2+1]=4](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B5%2B2%2B1%5D%3D4)
Number of bond pair = 2
Number of lone pair = 2
The total number of electron pair are 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
But as there are 2 atoms around the central oxygen atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular.
Hence, the correct option is, (B) bent, 2, and
Answer:
-6.78 × 10⁴ J
Explanation:
When water condenses (goes from the gaseous state to the liquid state) it releases energy in the form of heat. We can calculate this heat using the following expression.
Q = ΔH°cond × m
where,
Q is the heat released
ΔH°cond is the latent heat of condensation (ΔH°cond of water is -2260 J/g)
m is the mass
Q = ΔH°cond × m
Q = -2260 J/g × 30.0 g
Q = -6.78 × 10⁴ J
