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mezya [45]
4 years ago
10

Using the black numbers on the stopwatch to answer the questions. What is the most accurate reading of seconds as indicated by t

he long second hand? a. 5.3 b. 5.6 c. 7.2 d. 53 secs its for edg i found out it was 5.3 and tenth of seconds freebie
Physics
1 answer:
jenyasd209 [6]4 years ago
4 0

a. 5.3

should be your answer

hope I Helped!!!!

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An airplane flies 2500 miles east in 245 seconds what is the velocity of the plane?
forsale [732]

Speed = (distance) / (time)

Speed = (

Velocity = speed, and its direction

The velocity of the plane is 10.2 miles per second East.

(about 48 times the speed of sound)

8 0
3 years ago
Help me please. I’ll select brainliest!
pishuonlain [190]

Answer:

90 degrees

Explanation:

the answer is 90 because angle a has a square on the angle which means it is 90 degrees

8 0
3 years ago
Read 2 more answers
A support crossbeam on a high speed train is made from a titanium rod that has a length of 0.650m when measured by an observer o
Vilka [71]

Answer:

A) The crossbeam is moving relative to the observer on the platform so the height appears contracted.

Explanation:

The observer on the train and the beam are in the same reference frame. That means observer on the train will measure the proper length of the beam not the contracted length . the observer is outside and the plank is in the moving system,it will appear to be moving.

3 0
4 years ago
An aircraft with a mass of 10,000 kg starts from rest at sea level and takes off, then flies to a cruising speed of 620 km/h and
Natasha_Volkova [10]

Answer:

The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

Explanation:

Given that,

Mass of aircraft = 10000 kg

Speed = 620 km/h = 172.22 m/s

Altitude = 10 km = 1000 m

We calculate the change in potential energy

\Delta P.E=mg(h_{2}-h_{1})

\Delta P.E=10000\times9.8\times(10000-0)

\Delta P.E=10000\times9.8\times10000

\Delta P.E=980000000\ J

\Delta P.E=980\ MJ

For g = 10 m/s²,

The change in potential energy will be 1000 MJ.

We calculate the change in kinetic energy

\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)

\Delta K.E=148298642\ J

\Delta K.E=148.3\ MJ

For g = 10 m/s²,

The change in kinetic energy will be 150 MJ.

Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

7 0
3 years ago
A wave with a speed of 9 m/s and a frequency of 0.5 Hz has a λ of what?
patriot [66]

Wave speed = (wavelength) x (frequency)

Wavelength = (wave speed) / (frequency)

Wavelength = (9 m/s) / (0.5 Hz)

<em>Wavelength = 18 m</em>

6 0
3 years ago
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