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Natali [406]
3 years ago
9

Which of the following compounds will experience hydrogen bonding?

Chemistry
2 answers:
lora16 [44]3 years ago
7 0
I believe the answer is the first one <span>NaH</span>
Natalka [10]3 years ago
6 0

Answer:

HF will experience hydrogen bonding

Explanation:

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom (attached with an electronegative atom e.g. O, N and F) and an electronegative atom (O,N and F).

Hydrogen bonding generally appears in covalent molecules.

Among all four given molecules, HF and CH_{4} are covalent molecules.

In HF, F is a highly electronegative atom attached to a H atom through a covalent bond. Therefore F atoms gets partial negative charge and H atoms gets partial positive charge.

Hence an interaction arises between H atom and F atom resulting formation of H-bonding.

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What material could be used for a cup to keep coffee hot
nata0808 [166]

Answer:

Your answer could be: ceramic or stainless steel.

Explanation:

Glass, ceramic, and stainless steel are all good insulating materials for keeping coffee hot. Although, if you don't want to possibly burn yourself, don't use glass.

Have a great day/night! ^^

4 0
3 years ago
Wich is a characteristic shared by all arthropods?
svetlana [45]
I think the answer would be A.
I think! I could be wrong!
3 0
3 years ago
Read 2 more answers
Calculate the energy per photon (in J) associated with a frequency of 1260 kHz. Submit answer in scientific notation using the f
aniked [119]

Taking into account the definition of photon and energy of a photon, the energy per photon is 8.3538×10⁻³⁸ J.

<h3>Energy of a photon</h3>

Electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absortion, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression:

E=h×f

where:

  • E is the energy of a photon.
  • h is the Planck's constant h.
  • f is the frequency of electromagnetic radiation.

<h3>Energy per photon</h3>

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= 1260 kHz= 1,260,000 Hz= 1.26×10⁶ Hz (being 1 kHz=1000 Hz)

Replacing in the definition of energy of a photon:

E= 1.26×10⁶ Hz× 6.63×10⁻³⁴ Js

<u><em>E= 8.3538×10⁻³⁸ J</em></u>

Finally, the energy per photon is 8.3538×10⁻³⁸ J.

Learn more about energy of a photon:

brainly.com/question/8924116

brainly.com/question/6945706

brainly.com/question/8000078

#SPJ1

6 0
2 years ago
Solution A is a 1.00 L buffer solution that is 1.188 M in acetic acid and 1.188 M in sodium acetate. Acetic acid has a pKa of 4.
Tomtit [17]

Answer:

pH change is -0.07

Explanation:

Using H-H equation for acetic acid:

pH = pKa + log [Acetate salt] / [Acetic acid]

Replacing:

pH = 4.74 + log[1.188M] / [1.188M]

pH = 4.74

The HCl reacts with sodium acetate producing acetic acid, thus:

HCl + CH₃COONa → CH₃COOH + NaCl

That means the final moles of sodium acetate are initial moles - moles of HCl and moles of acetic acid are initial moles + moles of HCl.

As the volume of the buffer is 1.0L, initial moles of both substances are 1.188moles. After reaction, the moles are:

sodium acetate: 1.188mol - 0.1mol = 1.088mol

Acetic acid: 1.188mol + 0.1mol = 1.288mol

Using again H-H equation:

pH = 4.74 + log[1.088M] / [1.288M]

pH = 4.67

pH change is: 4.67 - 4.74 = -0.07

7 0
3 years ago
How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k
weeeeeb [17]
Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
8 0
3 years ago
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