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Natali [406]
3 years ago
9

Which of the following compounds will experience hydrogen bonding?

Chemistry
2 answers:
lora16 [44]3 years ago
7 0
I believe the answer is the first one <span>NaH</span>
Natalka [10]3 years ago
6 0

Answer:

HF will experience hydrogen bonding

Explanation:

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom (attached with an electronegative atom e.g. O, N and F) and an electronegative atom (O,N and F).

Hydrogen bonding generally appears in covalent molecules.

Among all four given molecules, HF and CH_{4} are covalent molecules.

In HF, F is a highly electronegative atom attached to a H atom through a covalent bond. Therefore F atoms gets partial negative charge and H atoms gets partial positive charge.

Hence an interaction arises between H atom and F atom resulting formation of H-bonding.

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ahrayia [7]
Density =  \frac{MASS}{VOLUME}

volume = (4.5 cm) * (5.2cm) * (6.0cm)
             =  140.40 cm³

since Mass =  1591 g

then Density = \frac{1591 g}{140.40 cm^{3} }

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8 0
3 years ago
Balanced chemical equation for the use of hydrogen fuel
Ganezh [65]
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3 0
4 years ago
How many core electrons are in a ground state atom of selenium?
Harman [31]
Electrons in an atom can be classified as core electrons and valence electrons. Valence electrons are those electrons which are present in valence shell and participates in bond formation. While, Core electrons are all remaining electrons which are not present in valence shell, hence not take part in bonding.

Atomic number of Selenium (Se) is 34 hence it has 34 electrons with following electronic configuration;

                          1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴

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             Core Electrons  =  28

Result:
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3 years ago
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Explanation:

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Answer:

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Explanation:

5 0
3 years ago
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