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3 years ago

A grasshopper leaps into the air from the edge of a vertical cliff. Assume that

1 answer:

7 0

Maximum height reached h = 7.15cm = 0.0715 m The horizontal distance b = 1.04 m Angle of jump = 49 degrees. We have v^2 = 2gh which here is (vsin theta)^2 = 2gh
v^2 = (2 x 9.81 x 0.0715) / sin^2 49 = 1.402 / -0.95^2 = 1.55 => v = 1.24 m/s
Time taken for flight = b / v Cos theta = 1.04 / (1.24 x cos49)
= 1.04 / 0.8135 =1.27 s
Time to reach maximum height = vsin theta / g = (1.24 x 0.95) / 9.8 = 0.12 s
Now time taken for top to ground = 1.27 - 0.12 = 1.15 s
So the total height H =1/2 gt = 1/2 x 9.8 x 1.15 = 5.635.
Now the height of the cliff = 5.635 - 0.0715 = 5.56 m

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The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.6 square inches. If a force of 5.6 lb

balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = $F_1=5.6 lb$

Area of the piston = $A_1=0.6 inches^2$

Force applied on the brakes = $F_2$

Area of the brakes = $A_2=1.8 inches^2$

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

$\frac{F_1}{A_2}=\frac{F_2}{A_2}$

$F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb$

16.8 lb is the force on the brake pad of one wheel.

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3 years ago

What material or device prevents the conducting of electricity?

PtichkaEL [24]

Answer:

Explanation:

An insulator. You can see ceramic insulators on telephone poles and power poles if you look carefully. If you live in a city, somewhere in that city is a power station. The insulators are huge. They have to be. The currents are very large in many cases.

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3 years ago

A wheel is rotating freely at angular speed 420 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi

Mashcka [7]

Answer:60 rev/min

Explanation:

Given

angular speed of first shaft $\omega _1=420\ rev/min$

Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment of inertia of first wheel so moment of inertia of second is 7 I

As there is no external torque therefore angular momentum is conserved

$L_1=L_2$

$I_1\omega _1=I_2\omega _2$

$I\times (420)=7 I\times (\omega _2)$

$\omega _2=\frac{420}{7}$

$\omega _2=60\ rev/min$

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3 years ago

Describe the phases of the moon along with a picture.

Alex787 [66]

Answer:

The eight Moon phases:

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The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

<h2>The 8 phases (in order) are:</h2>

New moon.
Waxing Crescent.
First Quarter.
Waxing Gibbous.
Full moon.
Waning Gibbous.
Third Quarter.
Waning Crescent.

Explanation:

Hope it is helpful....

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3 years ago

Read 2 more answers

Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app

Aleks04 [339]

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

θ = 30°

Learn more about the banking angle:brainly.com/question/26759099?r

#SPJ1

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2 years ago