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LiRa [457]
4 years ago
12

A wheel is rotating freely at angular speed 420 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi

ally at rest and with 7 times the rotational inertia of the first, is suddenly coupled to the same shaft. (a) What is the angular speed of the resultant combination of the shaft and two wheels
Physics
1 answer:
Mashcka [7]4 years ago
8 0

Answer:60 rev/min

Explanation:

Given

angular speed of first shaft \omega _1=420\ rev/min

Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment  of inertia of first wheel so moment of inertia of second is 7 I

As there is no external torque therefore angular momentum is conserved

L_1=L_2

I_1\omega _1=I_2\omega _2

I\times (420)=7 I\times (\omega _2)

\omega _2=\frac{420}{7}

\omega _2=60\ rev/min  

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a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120
harkovskaia [24]

0.56 A is the current of the secondary coil.

transformer is the device that transfer electric energy from one AC circuit to another.

we know that ;

I ∝ 1/n;

where I IS CURRENT and n is NUMBER OF TURNS.

(I) secondary = X A

(n) secondary = 100

(I)  primary  = 0.04 A

(n)  primary  = 1400

USING THIS-----> I ∝ 1/n;

=>

0.04 A/X A =100/1400

=>X=0.56 A

as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.

learn more about transformers-

brainly.com/question/26991007

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4 0
1 year ago
An underwater diver sees the sun 50° above horizontal. how high is the sun above the horizon to a fisherman in a boat above the
Usimov [2.4K]
Snell's law states that:

n1 Sin∅1 = n2 Sin ∅2

Where, medium 1 with (n1 = 1.33) is water and medium 2 with (n2 = 1) is the air, ∅1 = 90-50 = 40°

Therefore,
Sin ∅2 = n1/n2 *Sin ∅1 = 1.33/1 *Sin 40 = 0.4833=> ∅1 = Sin ^- (0.4833) = 28.9 °

The fisherman the sun at 61.1° (90-∅2) above the horizontal.
3 0
3 years ago
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity
miv72 [106K]

V = at + V0

where v0 is the initial speed, a is the acceleration and t is the time.

So:

v = 5m/s^2*5s + 25m/s = 50 m/s

4 0
3 years ago
Bismuth-210 has a half-life of 5 days. If you
Anton [14]

Answer:

A = 62.5 g

using half life formulas, plug in missing variables.

6 0
4 years ago
a rugby player passes the ball 5.34 m across the field, where it is caught at the same height as it left his hand. at what angle
MakcuM [25]

Answer:

31.035^{\circ}

Explanation:

x = Displacement in x direction = 5.34 m

t = Time taken to travel the displacement

y = Displacement in y direction = 0

u = Initial velocity of ball = 7.7 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Displacement in x direction is given by

x=u\cos\theta t\\\Rightarrow t=\dfrac{5.34}{7.7 \cos\theta}

Displacement in y direction is given by

y=u\sin\theta t-\dfrac{1}{2}gt^2\\\Rightarrow 0=7.7\sin\theta \dfrac{5.34}{7.7\cos\theta}-\dfrac{1}{2}\times 9.81 (\dfrac{5.34}{7.7\cos\theta})^2\\\Rightarrow 0=7.7\sin\theta-4.905\times \dfrac{5.34}{7.7\cos\theta}\\\Rightarrow 0=7.7^2\sin\theta \cos\theta-4.905\times 5.34\\\Rightarrow 0=7.7^2\dfrac{\sin2\theta}{2}-4.905\times 5.34\\\Rightarrow 0=7.7^2\sin2\theta-4.905\times5.34\times 2\\\Rightarrow \sin2\theta=\dfrac{4.905\times 5.34\times 2}{7.7^2}\\\Rightarrow 2\theta=\sin^{-1}\dfrac{4.905\times 5.34\times 2}{7.7^2}

\Rightarrow \theta=\dfrac{62.07}{2}\\\Rightarrow \theta=31.035^{\circ}

The angle at which the ball was thrown is 31.035^{\circ}.

7 0
3 years ago
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