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LiRa [457]
3 years ago
12

A wheel is rotating freely at angular speed 420 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi

ally at rest and with 7 times the rotational inertia of the first, is suddenly coupled to the same shaft. (a) What is the angular speed of the resultant combination of the shaft and two wheels
Physics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:60 rev/min

Explanation:

Given

angular speed of first shaft \omega _1=420\ rev/min

Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment  of inertia of first wheel so moment of inertia of second is 7 I

As there is no external torque therefore angular momentum is conserved

L_1=L_2

I_1\omega _1=I_2\omega _2

I\times (420)=7 I\times (\omega _2)

\omega _2=\frac{420}{7}

\omega _2=60\ rev/min  

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vodomira [7]

Answer:

Transform= not destroyed or created  

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Convergent= crust destroyed

Explanation:

The plates move in the opposite or away from each other at a transforming plate boundary. The two platform borders are not produced or destroyed in this case. As both plates converge on each other and thus destroy the plates for converging plate boundaries. When the plate is divergent, both plates shift away from each other by opening up and solidification for a new crust.

3 0
3 years ago
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A potential difference of 24 V is applied to a 150-ohm resistor. How much current flows through the resistor?​
Lady_Fox [76]

Given :- A resistor of 150 ohm, hence Resistance (R) = 150 ohm

Potential Difference (v) = 24 V

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3 0
3 years ago
Sound travels through air at 343 m/s,
sasho [114]

The sound wave will have traveled 2565 m  farther in water than in air.

Answer:

Explanation:

It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.

Distance = Velocity × Time.

So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.

As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.

Distance = 343 × 2.25 =771.75 m

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Distance = 1483×2.25=3337 m.

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Answer:

2) 433 mph

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