75.0 grams NaBr Find the molar mass and number of moles
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<h3>Answer:</h3>
64 g O₂
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O
[Given] 36 g H₂O
[Solve] x g O₂
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol O₂ → 2 mol H₂O
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mas of H - 1.01 g/mol
Molar Mass of O₂ - 2(16.00) = 32.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:
- Divide/Multiply [Cancel Units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
63.929 g O₂ ≈ 64 g O₂
511.2 grams of chlorine gas consumed (with excess H-) when
1,342.0 kJ of energy is released from the system.
<h3></h3><h3>What is an exothermic reaction?</h3>In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative."
Given that 1 mole of chlorine releases -184.6 energy.
Then, we have to find the number of moles of chlorine when 1,342.0 kJ of energy is released from the system.
So, calculating number of moles of chlorine.
Moles =
Moles = 7.2 mole
Now, calculating number mass of chlorine.
Mass = 7.2 mole x 71 g/mole
Mass = 511.2 gram
Learn more about exothermic reaction here:
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