Answer:
E = 4000 N/C
Explanation:
Given the following data;
Force = 0.080 N.
Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs
To find the electric field strength;
Mathematically, the electric field strength is given by the formula;
Electric field strength = force/charge
Substituting into the formula, we have;
E = 0.080/0.00002
E = 4000 N/C
The period of the wave is determined as 0.083 seconds.
<h3>What is period of a wave?</h3>
The period of a wave is the time taken by a particle of the medium to complete one vibration.
<h3>Period of the wave</h3>
The period of the wave is calculated as follows;
T = 1/f
where;
- T is the period of the wave
- f is frequency of the wave
T = 1/12
T = 0.083 seconds
Thus, the period of the wave is determined as 0.083 seconds.
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Answer:
Electric Field = E = 36.848 N/C
Explanation:
In accordance with Columb's law
E = k Q1 Q2 / r.r = 8.99 x 10^9 x 5.0 x 10^-6 x 5.8 x 10^-6 / 0.084 x 0.084
= 36948.6961 x 10^-3 = 36.848 N/C
Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g