Explanation:
- vector r lies on z- axis
- J is tilted at angle Ψ
- Orient x-axis such that w lies in x-z plane
Given:
Vector potential
Where, K = б*v ; r* = sqrt (R^2 + r^2 -2R*r*cos(θ')) ; da' = R^2*sin(θ')*dθ'dΦ'
Solution:
- Velocity of v point a point r' in a rotating rigid body is given by:
v = w x r' =
- where a = Ψ and b' = θ' and c' = Φ'
v = R*w [-(cos Ψ *sin θ' *sin Φ') x + (cos Ψ *sin θ' *cos Φ' - sin Ψ * cos θ') y
+ (cos Ψ *sin θ' *sin Φ') z ]
- Notice that terms like sin Φ' and cos Φ' contribute to zero:
- Hence,
- Evaluate integral u = cos (b')
- From we can determine two cases when r > R and r < R
Hence,
r < R
r > R
- Reverting back to original coordinate system given in figure 5.45:
r < R
r > R
Where, b = θ and c = direction along Φ.
Hence, A ( r , θ , Φ )
Answer:
<h2>450 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 250 × 1.8
We have the final answer as
<h3>450 N</h3>
Hope this helps you
first object gors highest
second object goes lowest.
Radio waves are a type of electromagnetic radiation with wavelengths in the electromagnetic spectrum
Hope it helps :)
499.15 is lines per millimeter needed in a diffraction grating if the lines are to be resolved in the second-order spectrum with a beam of width 0.10 mm.
the wave length of the sodium spectrum are λ1 = 589.0 nm and λ2 =589.59 nm
The resolving power of the grating is R = λ/Δλ =Nm.
Thus, the total number of lines needed on the grating to resolve the wavelengths in order m is
For the sodium doublet in the first order, N = λ /m(Δλ)
where λ = 589.0 nm , Δλ = 589.59 nm -589.0 nm = 0.59 nm
m = 2
The minimum number of lines in the grating
N = [589.0 nm] / [(2)( 0.59 nm )] = 499.15
To know more about spectrum visit : brainly.com/question/6836691
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