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Semmy [17]
3 years ago
10

There were 430 people at a play. The admission price was $3 for adults and $1 for children. The admission receipts were $890. Ho

w many adults and how many children attended?
Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

Step-by-step explanation:

Number of adults = a

Number of children = c

Total people  = 430

a + c = 430 --------------(I)

Total amount =$890

3a + c =890 -----------(II)

Multiply equation (I) by (-1)

(I)*(-1)    -a - c = -430

(II)         <u>3a + c = 890</u>    {Now add and thus c will be eliminated}

           2a        = 460

a = 460/2

a= 230

Plug in the value of a in equation (I)

230 + c = 430

c = 430 - 230

c = 200

Number of adults = 230

Number of children = 200

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Answer:

We conclude that the proportion of Americans who prefer to drink DD coffee is actually more than what was advertised.

Step-by-step explanation:

We are given that in a recent Dunkin Donuts (DD) commercial, it states that 58% of Americans prefer to drink their coffee.

Of the five hundred randomly selected people who were asked if they preferred DD coffees, 325 said they did.

<em>Let p = proportion of Americans who prefer to drink DD coffee</em>

SO, <u>Null Hypothesis</u>, H_0 : p \leq 58%   {means that the proportion of Americans who prefer to drink DD coffee is actually less than or equal to what was advertised}

<u>Alternate Hypothesis</u>, H_A : p > 58%   {means that the proportion of Americans who prefer to drink DD coffee is actually more than what was advertised}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where,  \hat p = sample proportion of people who prefer to drink DD coffee in a sample of 500 people = \frac{325}{500} = 65% or 0.65

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So, <em><u>test statistics</u></em>  =   \frac{0.65-0.58}{{\sqrt{\frac{0.65(1-0.65)}{500} } } } }

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<em>Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the proportion of Americans who prefer to drink DD coffee is actually more than what was advertised.

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